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05. Circular Motion 2

  • Page ID
    445
  • \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \) \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)\(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\) \(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\)\(\newcommand{\AA}{\unicode[.8,0]{x212B}}\)

    Polar Coordinates

    In the polar coordinate system, one axis (the radial axis, or rho hat.png is perpendicular to the surface of the circular path pointing radially away from the center, and the other axis (the tangential, or phi hat.png is parallel to the surface of the circular path pointing in the counterclockwise direction. (r is the lower-case Greek letter "rho" and f is "phi".)

    pic 1.png

    Notice that rho hat.png is inclined by an angle q from the positive x-axis. Therefore, in terms of i hat.png and j hat.png;

    pic 2.png

    phi hat.png, on the other hand, is inclined by an angle q to the left of the positive y-axis. Therefore, in terms of i hat.png and j hat.png;

    pic 3.png

    Now re-examine the relationships for position, velocity and acceleration.

    Position

    pic 4.png

    becomes

    pic 5.png

    In component form this is:

    pic 6.png

    This means that the position of an object undergoing circular motion is only in the radial direction, and has a constant magnitude equal to the radius of the circle. Basically, the coordinate system is constructed so that the location of the object defines the radial direction.

    Velocity

    pic 7.png

    becomes

    pic 8.png

    In component form this is:

    pic 9.png

    This means that the velocity of an object undergoing circular motion is only in the tangential direction, and has a magnitude equal to the product of the radius and angular velocity. The only way an object can have a radial velocity is if the radius of it path changes, but that can't happen for an object moving along a circular path. If the object moved along an elliptical path, for example, then it would have both tangential and radial velocities.

    Acceleration

    pic 10.png

    becomes

    pic 11.png

    In component form this is:

    pic 12.png

    The acceleration of an object undergoing circular motion has two components. If the object is speeding up or slowing down, the angular acceleration does not equal zero and there is an acceleraton component in the tangential direction. The magnitude of the tangential acceleration is equal to the product of the radius and angular acceleration.

    However, even if the object is moving at constant speed, there is an acceleration component in the negative radial direction, i.e., pointing toward the center of the circle. By virtue of traveling in a circle, the velocity vector of an object continually changes its orientation. This change in orientation is directed toward the center of the circle. Draw a motion diagram and convince yourself of this fact!

    The magnitude of the radial acceleration is equal to the product of the radius and the square of the angular velocity.

    Paul D’Alessandris (Monroe Community College)


    This page titled 05. Circular Motion 2 is shared under a CC BY-NC-SA license and was authored, remixed, and/or curated by Paul D'Alessandris.

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