Skip to main content
\(\require{cancel}\)
Physics LibreTexts

5.6: Capacitors in Series

  • Page ID
    5443

  • \(\text{FIGURE V.6}\)

    The charge is the same on each, and the potential difference across the system is the sum of the potential differences across the individual capacitances. Hence

    \[\dfrac{1}{C}=\dfrac{1}{C_1}+\dfrac{1}{C_2}+\dfrac{1}{C_3}.\label{5.6.1}\]