$$\require{cancel}$$

# 4.5: Conductors in Parallel


$$\text{FIGURE IV.3}$$

$G=G_1+G_2+G_3.\label{4.5.1}$

That is to say $\frac{1}{R} = \frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}.\label{4.5.2}$

The potential difference is the same across each. The current is greatest through the largest conductance – i.e. through the smallest resistance.

4.5: Conductors in Parallel is shared under a CC BY-NC 4.0 license and was authored, remixed, and/or curated by Jeremy Tatum via source content that was edited to conform to the style and standards of the LibreTexts platform; a detailed edit history is available upon request.