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4.3: A₂= 0

  • Page ID
    14768
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    In this case \(A_1=− B_3\), and the relation between \(k\) and \(κ\) is modified to

    \[k a = − κ a \cot κ a . \label{4.19}\]

    From the graphical solution, in Figure \(\PageIndex{1}\) we see that this type of solution only occurs for \(κ_0a\) greater than \(π∕ 2\).

    sq˙well˙odd

    Figure \(\PageIndex{1}\): The graphical solution for the odd states of the square well.

    In the middle region all these solutions behave like sines, and you will be asked to show that the solutions turn into minus themselves when \(x\) goes to \(− x\). (We say that these functions are odd.)


    This page titled 4.3: A₂= 0 is shared under a CC BY-NC-SA 2.0 license and was authored, remixed, and/or curated by Niels Walet via source content that was edited to the style and standards of the LibreTexts platform; a detailed edit history is available upon request.

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