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2.1: Orders of magnitude

  • Page ID
    19366
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    Although you should try to fight intuition when building a model to describe a particular phenomenon, you should not abandon critical thinking and should always ask if a prediction from your model makes sense. One of the most straightforward ways to estimate if a model makes sense is to ask whether it predicts the correct order of magnitude for a quantity. Usually, the order of magnitude for a quantity can be determined by making a very simple model, ideally one that you can work through in your head. When we say that a prediction gives the right “order of magnitude”, we usually mean that the prediction is within a factor of “a few” (up to a factor of 10) of the correct answer. For example, if a measurement gives a value of 2000, then we would consider that a model prediction of 8,000 gave the right order of magnitude (it differs from the correct answer by a factor of 4, whereas a prediction of 24,000 would not (it differs by a factor of 12).

    Example \(\PageIndex{1}\)

    How many ping pong balls can you fit into a school bus? Is it of order \(10,000\), or \(100,000\), or more?

    Solution

    Our strategy is to estimate the volumes of a school bus and of a ping pong ball, and then calculate how many times the volume of the ping pong ball fits into the volume of the school bus.

    We can model a school bus as a box, say \(20\:\text{m}×2\:\text{m}×2\:\text{m}\), with a volume of \(80\:\text{m}^{3}∼100\:\text{m}^{3}\).

    clipboard_efbb5caa765b24decf447f77d77a4aa86.png
    Figure \(\PageIndex{1}\): A school bus and ping pong balls modeled as boxes.

    We can model a ping pong ball as a sphere with a diameter of \(0.03\) m \((3\:\text{cm})\). When stacking the ping pong balls, we can model them as little cubes with a side given by their diameter, so the volume of a ping pong ball, for stacking, is \(∼ 0.00003\:\text{m}^{3}=3×10^{−5}\:\text{m}^{3}\). If we divide \(100\:\text{m}^{3}\) by \(3 × 10^{−5}\:m^{3}\), using scientific notation:

    \[\frac{100\:\text{m}^{3}}{3\times\:10^{-5}\text{m}^{3}}=\frac{1\times 10^{2}}{3\times 10^{-5}}=\frac{1}{3}\times 10^{7}\sim 3\times 10^{6}\]

    Thus, we expect to be able to fit about three million ping pong balls in a school bus.

    Exercise \(\PageIndex{1}\)

    Fill in the following table, giving the order of magnitude (in meters) of the sizes of different physical objects. Feel free to look these up on the internet!

    Table \(\PageIndex{1}\)
    Object Order of Magnitude
    Proton  
    Nucleus of atom  
    Hydrogen atom  
    Virus  
    Human skin cell  
    Width of human hair  
    Human \(1\) m
    Height of Mt. Everset  
    Radius of the Earth  
    Radius of the Sun  
    Radius of the Milky Way  
    Answer

    This page titled 2.1: Orders of magnitude is shared under a CC BY-SA 4.0 license and was authored, remixed, and/or curated by Ryan D. Martin, Emma Neary, Joshua Rinaldo, and Olivia Woodman via source content that was edited to the style and standards of the LibreTexts platform; a detailed edit history is available upon request.