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Physics LibreTexts

5.6: Capacitors in Series

  • Page ID
    5443
  • [ "article:topic", "authorname:tatumj" ]


    \(\text{FIGURE V.6}\)

    The charge is the same on each, and the potential difference across the system is the sum of the potential differences across the individual capacitances.  Hence

    \[\dfrac{1}{C}=\dfrac{1}{C_1}+\dfrac{1}{C_2}+\dfrac{1}{C_3}.\label{5.6.1}\]