1.6F: Field of a Uniformly Charged Infinite Plane Sheet
- Page ID
- 6477
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All we have to do is to put \(α = π/2\) in equation 1.6.10 to obtain
\[E=\frac{\sigma}{2\epsilon_0}.\tag{1.6.12}\]
This is independent of the distance of P from the infinite charged sheet. The electric field lines are uniform parallel lines extending to infinity.
Summary
\(\begin{align}&\text{Point charge Q :}\quad \quad \quad &&E=\frac{Q}{4\pi\epsilon_0 r^2}. \\ &\text{Hollow Spherical Shell: } &&E=\text{ zero inside the shell,} \\ & &&E=\frac{Q}{4\pi\epsilon_0 r^2}\text{ outside the shell} \\ &\text{Infinite charged rod :} &&E=\frac{\lambda}{2\pi\epsilon_0 r}. \\ &\text{Infinite plane sheet :} &&E=\frac{\sigma}{2\epsilon_0}. \end{align}\)