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5.11: Interference and polarisation
https://phys.libretexts.org/Bookshelves/Optics/BSc_Optics_(Konijnenberg_Adam_and_Urbach)/05%3A_Interference_and_coherence/5.11%3A_Interference_and_polarisation
Then ( $\PageIndex{2}$ ) becomes \[\mathcal{E}_{1} \cdot \mathcal{E}_{1}+\mathcal{E}_{2} \cdot \mathcal{E}_{2}+2 \mathcal{E}_{1} \cdot \mathcal{E}_{2}=\mathcal{E}_{1 \perp}^{2}+\mathcal{E}_{2 \perp}^{...Then ( $\PageIndex{2}$ ) becomes $\mathcal{E}_{1} \cdot \mathcal{E}_{1}+\mathcal{E}_{2} \cdot \mathcal{E}_{2}+2 \mathcal{E}_{1} \cdot \mathcal{E}_{2}=\mathcal{E}_{1 \perp}^{2}+\mathcal{E}_{2 \perp}^{2}+2 \mathcal{E}_{1 \perp} \mathcal{E}_{2 \perp}+\mathcal{E}_{1 \|}^{2}+\mathcal{E}_{2 \|}^{2}+2 \mathcal{E}_{1 \|} \mathcal{E}_{2 \|} \nonumber$

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