We can see that the voltage leads on the current if the reactance is positive; that is, if the inductive reactance is greater than the capacitive reactance; that is, if \(\omega > 1/\sqrt{LC}\). (Reca...We can see that the voltage leads on the current if the reactance is positive; that is, if the inductive reactance is greater than the capacitive reactance; that is, if \(\omega > 1/\sqrt{LC}\). (Recall that the frequency, \(\nu\), is \(\omega/(2\pi)\)).