Here Λ′ is now a different ratio than the one obtained for the alpha particles, but with a similar meaning: \(\Lambda^{\prime} = \sqrt{\frac{T}{2 m_{e} v^{2}}} \frac{\left(T+m c^{2}...Here Λ′ is now a different ratio than the one obtained for the alpha particles, but with a similar meaning: Λ′=√T2mev2(T+mc2)EI, where again we can recognize the ratio of the electron energy (determining the minimum distance) and the mean excitation energy EI (which sets the maximum distance) as well as a correction due to relativistic effects.
