it depends on the volume of the floating object (or, if it is not fully submerged, the volume that is under the surface) and on the density of the liquid. We could have measured the mass of the gradua...it depends on the volume of the floating object (or, if it is not fully submerged, the volume that is under the surface) and on the density of the liquid. We could have measured the mass of the graduated cylinder instead; however, the graduated cylinder has a higher mass (getting close to the maximum of the analytical balance) and an awkward shape for use in the balance.
An exponential fit of the solubility to temperature gives the same information as a linear fit of the natural log of solubility to temperature, and so the slope of the bottom graph (m=0.025) is the va...An exponential fit of the solubility to temperature gives the same information as a linear fit of the natural log of solubility to temperature, and so the slope of the bottom graph (m=0.025) is the value of m in the exponential function, and the y intercept of the bottom graph gives the pre-expontial, b=-1.39=lna, so a = e -1.39 .