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    About 16 results
    • https://phys.libretexts.org/Courses/Joliet_Junior_College/Physics_201_-_Fall_2019v2/Book%3A_Custom_Physics_textbook_for_JJC/07%3A_Applications_of_Newton/7.11%3A_Introduction_to_UCM_and_Gravitation
      Uniform circular motion is a motion in a circular path at constant speed.
    • https://phys.libretexts.org/Bookshelves/University_Physics/Physics_(Boundless)/5%3A_Uniform_Circular_Motion_and_Gravitation/5.1%3A_Introduction_to_UCM_and_Gravitation
      Uniform circular motion is a motion in a circular path at constant speed.
    • https://phys.libretexts.org/Bookshelves/University_Physics/University_Physics_(OpenStax)/Book%3A_University_Physics_I_-_Mechanics_Sound_Oscillations_and_Waves_(OpenStax)/05%3A_Newton's_Laws_of_Motion/5.07%3A_Common_Forces
      When an object rests on a nonaccelerating horizontal surface, the magnitude of the normal force is equal to the weight of the object. On an inclined plane, the weight of the object can be resolved int...When an object rests on a nonaccelerating horizontal surface, the magnitude of the normal force is equal to the weight of the object. On an inclined plane, the weight of the object can be resolved into components that act perpendicular and parallel to the surface of the plane. When a rope supports the weight of an object at rest, the tension in the rope is equal to the weight of the object. The force developed in a spring obeys Hooke’s law.
    • https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Physics_I_(2211)/05%3A_Forces/5.03%3A_Common_Forces_-_Normal_(or_Perpendicular)_Force
      Figure \PageIndex2: Since the acceleration is parallel to the slope and acting down the slope, it is most convenient to project all forces onto a coordinate system where one axis is parallel to ...Figure \PageIndex2: Since the acceleration is parallel to the slope and acting down the slope, it is most convenient to project all forces onto a coordinate system where one axis is parallel to the slope and the other is perpendicular to it (axes shown to the left of the skier). FN is perpendicular to the slope and Ff is parallel to the slope, but Fg has components along both axes, namely, w y and w x . Here, Fg has a squiggly line to show that …
    • https://phys.libretexts.org/Courses/Tuskegee_University/Algebra_Based_Physics_I/04%3A_Dynamics-_Force_and_Newton's_Laws_of_Motion/4.06%3A_Normal%2C_Tension%2C_and_Other_Examples_of_Forces
      Forces are given many names, such as push, pull, thrust, lift, weight, friction, and tension. Traditionally, forces have been grouped into several categories and given names relating to their source, ...Forces are given many names, such as push, pull, thrust, lift, weight, friction, and tension. Traditionally, forces have been grouped into several categories and given names relating to their source, how they are transmitted, or their effects. The most important of these categories are discussed in this section, together with some interesting applications. Further examples of forces are discussed later in this text.
    • https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Physics_I_(2211)/05%3A_Forces/5.07%3A_Common_Forces_-_Stress_Strain_and_the_Spring_Force
      The pillar’s cross-sectional area is 0.20 m 2 and it is made of granite with a mass density of 2700 kg/m 3 . Find the compressive stress at the cross-section located 3.0 m below the top of the pillar ...The pillar’s cross-sectional area is 0.20 m 2 and it is made of granite with a mass density of 2700 kg/m 3 . Find the compressive stress at the cross-section located 3.0 m below the top of the pillar and the value of the compressive strain of the top 3.0-m segment of the pillar. Unlike in the previous example, however, if the weight of the rod is taken into consideration, the stress in the rod is largest at the top and smallest at the bottom of the rod where the equipment is attached.
    • https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Physics_I_(2211)/05%3A_Forces/5.06%3A_Common_Forces_-_Tension
      Figure \PageIndex5: (a) Tendons in the finger carry force T from the muscles to other parts of the finger, usually changing the force’s direction but not its magnitude (the tendons are relativel...Figure \PageIndex5: (a) Tendons in the finger carry force T from the muscles to other parts of the finger, usually changing the force’s direction but not its magnitude (the tendons are relatively friction free). (b) The brake cable on a bicycle carries the tension T from the brake lever on the handlebars to the brake mechanism.
    • https://phys.libretexts.org/Workbench/PH_245_Textbook_V2/03%3A_Module_2_-_Multi-Dimensional_Mechanics/3.03%3A_Objective_2.c./3.3.06%3A_Common_Forces
      When an object rests on a nonaccelerating horizontal surface, the magnitude of the normal force is equal to the weight of the object. On an inclined plane, the weight of the object can be resolved int...When an object rests on a nonaccelerating horizontal surface, the magnitude of the normal force is equal to the weight of the object. On an inclined plane, the weight of the object can be resolved into components that act perpendicular and parallel to the surface of the plane. When a rope supports the weight of an object at rest, the tension in the rope is equal to the weight of the object. The force developed in a spring obeys Hooke’s law.
    • https://phys.libretexts.org/Courses/Joliet_Junior_College/Physics_201_-_Fall_2019/Book%3A_Physics_(Boundless)/05%3A_The_Laws_of_Motion/5.14%3A_Common_Forces
      When an object rests on a nonaccelerating horizontal surface, the magnitude of the normal force is equal to the weight of the object. On an inclined plane, the weight of the object can be resolved int...When an object rests on a nonaccelerating horizontal surface, the magnitude of the normal force is equal to the weight of the object. On an inclined plane, the weight of the object can be resolved into components that act perpendicular and parallel to the surface of the plane. When a rope supports the weight of an object at rest, the tension in the rope is equal to the weight of the object. The force developed in a spring obeys Hooke’s law.
    • https://phys.libretexts.org/Courses/Muhlenberg_College/MC%3A_Physics_121_-_General_Physics_I/06%3A_Newton's_Laws_of_Motion/6.07%3A_Common_Forces
      When an object rests on a nonaccelerating horizontal surface, the magnitude of the normal force is equal to the weight of the object. On an inclined plane, the weight of the object can be resolved int...When an object rests on a nonaccelerating horizontal surface, the magnitude of the normal force is equal to the weight of the object. On an inclined plane, the weight of the object can be resolved into components that act perpendicular and parallel to the surface of the plane. When a rope supports the weight of an object at rest, the tension in the rope is equal to the weight of the object. The force developed in a spring obeys Hooke’s law.
    • https://phys.libretexts.org/Courses/Joliet_Junior_College/Physics_201_-_Fall_2019v2/Book%3A_Custom_Physics_textbook_for_JJC/06%3A_The_Laws_of_Motion/6.14%3A_Common_Forces
      When an object rests on a nonaccelerating horizontal surface, the magnitude of the normal force is equal to the weight of the object. On an inclined plane, the weight of the object can be resolved int...When an object rests on a nonaccelerating horizontal surface, the magnitude of the normal force is equal to the weight of the object. On an inclined plane, the weight of the object can be resolved into components that act perpendicular and parallel to the surface of the plane. When a rope supports the weight of an object at rest, the tension in the rope is equal to the weight of the object. The force developed in a spring obeys Hooke’s law.

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