The real part of such a \(\overrightarrow{\mathrm{\underline k}}\) is so large that even for grazing angles of incidence, θ i ≅ 90 o , the transmission angle θ t must be nearly zero in order to match ...The real part of such a \(\overrightarrow{\mathrm{\underline k}}\) is so large that even for grazing angles of incidence, θ i ≅ 90 o , the transmission angle θ t must be nearly zero in order to match phases, as suggested by Figure 9.2.3(a) in the limit where kt is orders of magnitude greater than k i . As a result, the power dissipated in the conductor is essentially the same as for θ i = 0 o , and therefore depends in a simple way on the induced surface current and parallel surface magnetic fi…
