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    • https://phys.libretexts.org/Bookshelves/Electricity_and_Magnetism/Electromagnetics_and_Applications_(Staelin)/10%3A_Antennas_and_Radiation/10.01%3A_Radiation_from_charges_and_currents
      51 Let A=Φ+×N; then \(\nabla \times \overrightarrow{\mathrm{A}}=\nabla \times(\nabla \times \overrightarrow{\mathrm{N}})...51 Let A=Φ+×N; then ×A=×(×N) and A=2Φ, so ×A and A can be chosen independently simply by choosing N and Φ independently.

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