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    • https://phys.libretexts.org/Bookshelves/Classical_Mechanics/Classical_Mechanics_(Tatum)/06%3A_Motion_in_a_Resisting_Medium/6.03%3A_Uniformly_Accelerated_Motion/6.3C%3A_Body_thrown_vertically_upwards%2C_initial_speed_(v_0)
      \[ v = -\hat{v} + (v_{0}+\hat{v})e^{- \gamma t} \tag{6.3.25}\label{eq:6.3.25} \] The second time integral (obtained by writing \( v\) as \( \frac{dy}{dt}\) in Equation \(\ref{eq:6.3.25}\)) and the spa...\[ v = -\hat{v} + (v_{0}+\hat{v})e^{- \gamma t} \tag{6.3.25}\label{eq:6.3.25} \] The second time integral (obtained by writing \( v\) as \( \frac{dy}{dt}\) in Equation \(\ref{eq:6.3.25}\)) and the space integral (obtained by writing \( \ddot{y} \) as \( v\frac{dv}{dy}\) in the equation of motion) require some patience, but the results are \[ v = v_{0} - \gamma y -\hat{v}\ln \left(\frac{\hat{v}+v_{0}}{\hat{v}+v}\right). \tag{6.3.28}\label{eq:6.3.28} \]

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