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- https://phys.libretexts.org/Bookshelves/Classical_Mechanics/Classical_Mechanics_(Tatum)/20%3A_Miscellaneous/20.03%3A_Shear_Modulus_and_Torsion_ConstantThe material will undergo an angular deformation, and the ratio of the tangential force per unit area to the resulting angular deformation is called the shear modulus or the rigidity modulus.
- https://phys.libretexts.org/Courses/Prince_Georges_Community_College/General_Physics_I%3A_Classical_Mechanics/50%3A_Elasticity/50.04%3A_Transverse_(Shear)_StressTorsionalThen the strain is the arc length s through which the cylinder is twisted, divided by the length of the cylinder: ε=s/ℓ. In the case of the torsional transverse stress on a cyli...Then the strain is the arc length s through which the cylinder is twisted, divided by the length of the cylinder: ε=s/ℓ. In the case of the torsional transverse stress on a cylinder of length ℓ and radius r twisted through an angle θ by a torque τ, it can be shown that the shear modulus is
- https://phys.libretexts.org/Courses/Joliet_Junior_College/Physics_201_-_Fall_2019v2/Book%3A_Custom_Physics_textbook_for_JJC/10%3A_Static_Equilibrium_Elasticity_and_Torque/10.04%3A_Stress_Strain_and_Elastic_Modulus_(Part_1)External forces on an object cause its deformation, which is a change in its size and shape. The strength of the forces that cause deformation is expressed by stress. The extent of deformation under s...External forces on an object cause its deformation, which is a change in its size and shape. The strength of the forces that cause deformation is expressed by stress. The extent of deformation under stress is expressed by strain, which is dimensionless. Tensile (or compressive) stress, which causes elongation (or shortening) of the object or medium and is due to external forces acting along only one direction perpendicular to the cross-section.
- https://phys.libretexts.org/Courses/Prince_Georges_Community_College/General_Physics_I%3A_Classical_Mechanics/52%3A_Fluid_Dynamics/52.06%3A_ViscosityRecall from the study of elasticity (Chapter 50) that when a body is placed under transverse (shear) stress σ=Ft/A, the resulting strain ε is the tangential displacement \(...Recall from the study of elasticity (Chapter 50) that when a body is placed under transverse (shear) stress σ=Ft/A, the resulting strain ε is the tangential displacement x divided by the transverse distance l : Fluid flow undergoes a similar kind of shear stress; however, with fluids, we find that the stress is not proportional to the strain, but to the rate of change of strain:
- https://phys.libretexts.org/Courses/Prince_Georges_Community_College/General_Physics_I%3A_Classical_Mechanics/50%3A_Elasticity/50.03%3A_Transverse_(Shear)_StressTranslationalNow put your hand on the front cover and push the cover to the right, so that the front cover moves to the right but the rear cover remains stationary on the table (by friction). 50.1.2, where the for...Now put your hand on the front cover and push the cover to the right, so that the front cover moves to the right but the rear cover remains stationary on the table (by friction). 50.1.2, where the force F is the component of the force parallel to the surface (front cover of the book), and A is the area of the surface (the area of the book cover).
- https://phys.libretexts.org/Bookshelves/University_Physics/University_Physics_(OpenStax)/Book%3A_University_Physics_I_-_Mechanics_Sound_Oscillations_and_Waves_(OpenStax)/12%3A_Static_Equilibrium_and_Elasticity/12.04%3A_Stress_Strain_and_Elastic_Modulus_(Part_1)External forces on an object cause its deformation, which is a change in its size and shape. The strength of the forces that cause deformation is expressed by stress. The extent of deformation under s...External forces on an object cause its deformation, which is a change in its size and shape. The strength of the forces that cause deformation is expressed by stress. The extent of deformation under stress is expressed by strain, which is dimensionless. Tensile (or compressive) stress, which causes elongation (or shortening) of the object or medium and is due to external forces acting along only one direction perpendicular to the cross-section.
- https://phys.libretexts.org/Courses/Joliet_Junior_College/Physics_201_-_Fall_2019/Book%3A_Physics_(Boundless)/09%3A_Static_Equilibrium_Elasticity_and_Torque/9.1%3A_Static_Equilibrium_and_Elasticity/Stress_Strain_and_Elastic_Modulus_(Part_1)External forces on an object cause its deformation, which is a change in its size and shape. The strength of the forces that cause deformation is expressed by stress. The extent of deformation under s...External forces on an object cause its deformation, which is a change in its size and shape. The strength of the forces that cause deformation is expressed by stress. The extent of deformation under stress is expressed by strain, which is dimensionless. Tensile (or compressive) stress, which causes elongation (or shortening) of the object or medium and is due to external forces acting along only one direction perpendicular to the cross-section.
- https://phys.libretexts.org/Courses/Prince_Georges_Community_College/General_Physics_I%3A_Classical_Mechanics/50%3A_Elasticity/50.01%3A_Introduction_to_Elasticitywhere σ is the stress, ε is the strain, and E is the elastic modulus, which takes the place of the spring constant in Hooke's law. In Eq. \PageIndex1, the stress \(\si...where σ is the stress, ε is the strain, and E is the elastic modulus, which takes the place of the spring constant in Hooke's law. In Eq. \PageIndex1, the stress σ and elastic modulus E both have units of N/m2; the strain ε is dimensionless. In all cases, the stress σ is defined as the force F applied to the body, divided by the area A over which the force acts:
