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- https://phys.libretexts.org/Bookshelves/University_Physics/Book%3A_Spiral_Physics_-_Calculus_Based_(DAlessandris)/Spiral_Mechanics_(Calculus-Based)/04%3A_Model_3/4.03%3A_New_PageNote that when the block is at a positive position, the force of the spring is in the negative direction and when the block is at a negative position, the force of the spring is in the positive direct...Note that when the block is at a positive position, the force of the spring is in the negative direction and when the block is at a negative position, the force of the spring is in the positive direction. Determine the speed of the cart (v) as a function of the angular position of the cart on the loop (let straight down be θ =0°), the spring constant (k), the initial compression of the spring (s), H, m, and g.
- https://phys.libretexts.org/Bookshelves/University_Physics/Book%3A_Spiral_Physics_-_Calculus_Based_(DAlessandris)/Spiral_Electricity_and_Magnetism__(Calculus-Based)/7%3A_Electric_Circuits/04._Activities/XI_-_38This page has no content. Enrich PhysWiki by contributing.
- https://phys.libretexts.org/Bookshelves/University_Physics/Book%3A_Spiral_Physics_-_Calculus_Based_(DAlessandris)/Spiral_Electricity_and_Magnetism__(Calculus-Based)/7%3A_Electric_Circuits/04._Activities/XI_-_20This page has no content. Enrich PhysWiki by contributing.
- https://phys.libretexts.org/Bookshelves/University_Physics/Book%3A_Spiral_Physics_-_Calculus_Based_(DAlessandris)/Spiral_Mechanics_(Calculus-Based)/03%3A_Model_2/3.00%3A_New_PageFor our second pass through the study of mechanics, we will eliminate one of the major restrictions in our original model. We will now allow objects to move through three dimensional space. We will st...For our second pass through the study of mechanics, we will eliminate one of the major restrictions in our original model. We will now allow objects to move through three dimensional space. We will still, however, restrict our model with the following approximations. The object is acted on by constant forces. The object’s size and shape are unimportant. The object is classical.
- https://phys.libretexts.org/Bookshelves/University_Physics/Book%3A_Spiral_Physics_-_Calculus_Based_(DAlessandris)/Spiral_Mechanics_(Calculus-Based)/02%3A_Model_1/2.02%3A_New_PageNotice that between the instant she hits the brakes and the instant she steps on the gas the acceleration is negative, while between the instant she steps on the gas and the instant she passes the lig...Notice that between the instant she hits the brakes and the instant she steps on the gas the acceleration is negative, while between the instant she steps on the gas and the instant she passes the light the acceleration is positive.
- https://phys.libretexts.org/Bookshelves/University_Physics/Book%3A_Spiral_Physics_-_Calculus_Based_(DAlessandris)/Spiral_Mechanics_(Calculus-Based)/05%3A_Model_4/5.01%3A_New_PageSince the point on the pulley attached to the block is accelerating at 0.75 m/s 2 , the block itself must be accelerating at 0.75 m/s 2 . In a nutshell, what we’ve done is used the acceleration of the...Since the point on the pulley attached to the block is accelerating at 0.75 m/s 2 , the block itself must be accelerating at 0.75 m/s 2 . In a nutshell, what we’ve done is used the acceleration of the truck to find the angular acceleration of the pulley, and then used the angular acceleration of the pulley to find the acceleration of the block.
- https://phys.libretexts.org/Bookshelves/University_Physics/Book%3A_Spiral_Physics_-_Calculus_Based_(DAlessandris)/Spiral_Mechanics_(Calculus-Based)/03%3A_Model_2/3.5%3A_Selected_Answers2 v1 = 11.2 m/s 4 v1 = 3.28 m/s 5 v1 = 31.4 m/s 6 The ball hits people in the stands behind home plate. (It sails 10.7 m above home plate.) 16 t2 = 40 s a = 0.15 m/s 2 19 t2 = 33.5 s θ = 188°...2 v1 = 11.2 m/s 4 v1 = 3.28 m/s 5 v1 = 31.4 m/s 6 The ball hits people in the stands behind home plate. (It sails 10.7 m above home plate.) 16 t2 = 40 s a = 0.15 m/s 2 19 t2 = 33.5 s θ = 188° from line initially between ship and man 21 a = 0 m/s 2 22 a = 0.94 m/s 2 26 a = 1.39 m/s 2 down 27 a = 0.84 m/s 2 34 a = 0.73 m/s 2 35 a = 0.66 m/s 2 36 a = 0 m/s 2 v2 = 2.52 m/s b. 45 v2 = 27 m/s 47 v2 = 14.9 m/s 48 v2 = 8.89 m/s 49 v2 = 14.3 m/s 51 v2 = 5.8 m/s 52 v2audi = 12.8 m/s
- https://phys.libretexts.org/Bookshelves/University_Physics/Book%3A_Spiral_Physics_-_Calculus_Based_(DAlessandris)/Spiral_Electricity_and_Magnetism__(Calculus-Based)/7%3A_Electric_Circuits/03._Analysis_Tools_2The dashed area is the area over which we will calculate the flux. (The current along the inner wire flows toward the top of the page, resulting in magnetic field pointing directly out of the page in ...The dashed area is the area over which we will calculate the flux. (The current along the inner wire flows toward the top of the page, resulting in magnetic field pointing directly out of the page in the area of interest.) This equation says that the time derivative of the derivative of the current is equal to the product of the derivative of the current and a numerical factor.
- https://phys.libretexts.org/Bookshelves/University_Physics/Book%3A_Spiral_Physics_-_Calculus_Based_(DAlessandris)/Spiral_Electricity_and_Magnetism__(Calculus-Based)/7%3A_Electric_Circuits/04._Activities/XI_-_31This page has no content. Enrich PhysWiki by contributing.
- https://phys.libretexts.org/Bookshelves/University_Physics/Book%3A_Spiral_Physics_-_Calculus_Based_(DAlessandris)/Spiral_Mechanics_(Calculus-Based)/04%3A_Model_3/4.01%3A_New_PageIn the polar coordinate system, one axis (the radial axis, or ˆr) is perpendicular to the surface of the circular path pointing radially away from the center, and the other axis (the tangenti...In the polar coordinate system, one axis (the radial axis, or ˆr) is perpendicular to the surface of the circular path pointing radially away from the center, and the other axis (the tangential, or ˆt) is parallel to the surface of the circular path pointing in the counterclockwise direction.
- https://phys.libretexts.org/Bookshelves/University_Physics/Book%3A_Spiral_Physics_-_Calculus_Based_(DAlessandris)/Spiral_Mechanics_(Calculus-Based)/03%3A_Model_2/3.01%3A_New_PageThus, by applying the kinematic relations in both the horizontal and vertical directions, you should be able to determine the initial velocity of the shot-put, the time in the air, and the final horiz...Thus, by applying the kinematic relations in both the horizontal and vertical directions, you should be able to determine the initial velocity of the shot-put, the time in the air, and the final horizontal and vertical velocity components. Since our analysis stops the instant before contact, note that the shot is still moving at this instant. (If it wasn’t, how could it ever reach the ground?) Thus, resist the temptation to think that the velocity of the shot is zero at the end of analysis.
