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- https://phys.libretexts.org/Courses/Coalinga_College/Physical_Science_for_Educators_(CID%3A_PHYS_14)/10%3A_Forces/10.02%3A_WeightThe gravitational force of the moon is one-sixth the magnitude of the gravitational force of the Earth; the weight of the moon rock on the moon will be one-sixth the weight of the moon rock on the Ear...The gravitational force of the moon is one-sixth the magnitude of the gravitational force of the Earth; the weight of the moon rock on the moon will be one-sixth the weight of the moon rock on the Earth’s surface.
- https://phys.libretexts.org/Courses/Coalinga_College/Physical_Science_for_Educators_(CID%3A_PHYS_14)/10%3A_Forces/10.05%3A_FrictionThe coefficient of kinetic friction between box A and the table is 0.20. (Ignore the masses of the rope and the pulley and any friction in the pulley.) The mass of box A is 5.0 kg and the mass of box ...The coefficient of kinetic friction between box A and the table is 0.20. (Ignore the masses of the rope and the pulley and any friction in the pulley.) The mass of box A is 5.0 kg and the mass of box B is 2.0 kg. The force acting to move the system is the weight of box B, and the force resisting the movement is the force of friction between the table and box A.
- https://phys.libretexts.org/Courses/Coalinga_College/Physical_Science_for_Educators_(CID%3A_PHYS_14)/09%3A_Motion/9.02%3A_Introduction-_Fundamentals_of_Motion-_Scientific_Overview/9.2.03%3A_Resolving_Vectors_into_ComponentsOne of the methods we can use to add these vectors is to resolve each one into a pair of vectors that lay on the north-south and east-west axes. The two vectors we are to add is a force of 65 N at 30°...One of the methods we can use to add these vectors is to resolve each one into a pair of vectors that lay on the north-south and east-west axes. The two vectors we are to add is a force of 65 N at 30° north of east and a force of 35 N at 60° north of west. Using trigonometry, we can resolve (break down) each of these vectors into a pair of vectors that lay on the axial lines (shown in red above).
- https://phys.libretexts.org/Courses/Coalinga_College/Physical_Science_for_Educators_(CID%3A_PHYS_14)/09%3A_Motion/9.03%3A_Motion_in_One-Dimension/9.3.04%3A_Instantaneous_VelocityIf the object is moving with constant velocity, then the instantaneous velocity at every moment, the average velocity, and the constant velocity are all the same. In the image above, the red line is t...If the object is moving with constant velocity, then the instantaneous velocity at every moment, the average velocity, and the constant velocity are all the same. In the image above, the red line is the position vs time graph and the blue line is an approximated slope for the line at t=2.5 seconds. For constant velocity motion, the slope gives the constant velocity, the average velocity, and the instantaneous velocity at every point.
- https://phys.libretexts.org/Courses/Coalinga_College/Physical_Science_for_Educators_(CID%3A_PHYS_14)/09%3A_Motion/9.02%3A_Introduction-_Fundamentals_of_Motion-_Scientific_Overview/9.2.04%3A_Vector_AdditionThe sum of the two vectors is the vector that begins at the origin of the first vector and goes to the ending of the second vector, as shown below. The resultant, or sum, vector would be the vector fr...The sum of the two vectors is the vector that begins at the origin of the first vector and goes to the ending of the second vector, as shown below. The resultant, or sum, vector would be the vector from the origin of the first vector to the arrowhead of the last vector; the magnitude and direction of this sum vector would then be measured.
- https://phys.libretexts.org/Courses/Fresno_City_College/NATSCI-1A%3A_Natural_Science_for_Educators_Fresno_City_College_(CID%3A_PHYS_140)/12%3A_Reflections_and_Refraction_of_Waves/12.02%3A_Optics/12.2.06%3A_Convex_MirrorsIn convex mirrors, the reflecting surface is on the outside of the sphere, making the center of curvature and the focal point on the opposite side of the mirror from the object. For convex mirrors, th...In convex mirrors, the reflecting surface is on the outside of the sphere, making the center of curvature and the focal point on the opposite side of the mirror from the object. For convex mirrors, the reflecting surface is on the outside of the sphere, placing the center of curvature and the focal point on the opposite side of the mirror from the object. Since the focal point is on the opposite side of the mirror from the object, the focal length is assigned a negative number.
- https://phys.libretexts.org/Courses/Fresno_City_College/NATSCI-1A%3A_Natural_Science_for_Educators_Fresno_City_College_(CID%3A_PHYS_140)/03%3A_Motion/3.02%3A_Motion_in_One-Dimension/3.2.05%3A_Average_AccelerationAverage acceleration, a, is defined as the rate of change of velocity, or the change in velocity per unit time. If the initial velocity is +15.0 m/s and 5.0 s is required to slow down to +5.0 m/s, wha...Average acceleration, a, is defined as the rate of change of velocity, or the change in velocity per unit time. If the initial velocity is +15.0 m/s and 5.0 s is required to slow down to +5.0 m/s, what was the car’s acceleration? Average acceleration is the rate of change of velocity, or the change in velocity per unit time. If an automobile slows from +26 m/s to +18 m/s in a period of 4.0 s, what was the average acceleration?
- https://phys.libretexts.org/Courses/Fresno_City_College/NATSCI-1A%3A_Natural_Science_for_Educators_Fresno_City_College_(CID%3A_PHYS_140)/06%3A_Circular_Motion_and_Gravity/6.01%3A_Circular_MotionThe acceleration in the case of uniform circular motion is the change in the direction of the velocity, but not its magnitude. For an object traveling in a circular path, the centripetal acceleration ...The acceleration in the case of uniform circular motion is the change in the direction of the velocity, but not its magnitude. For an object traveling in a circular path, the centripetal acceleration is directly related to the square of the velocity of the object and inversely related to the radius of the circle. We first determine the velocity of the ball using the facts that the circumference of the circle is 2πr and the ball goes around exactly twice per second.
- https://phys.libretexts.org/Courses/Fresno_City_College/NATSCI-1A%3A_Natural_Science_for_Educators_Fresno_City_College_(CID%3A_PHYS_140)/12%3A_Reflections_and_Refraction_of_Waves/12.02%3A_Optics/12.2.07%3A_Double_Convex_LensesAt least one of the faces is a part of a sphere; a convex lens is thicker at the center than the edges, and a concave lens is thicker at the edges than the center. If the object is placed inside F (be...At least one of the faces is a part of a sphere; a convex lens is thicker at the center than the edges, and a concave lens is thicker at the edges than the center. If the object is placed inside F (between F and the lens), the image will be on the same side of the lens as the object and it will be virtual, upright, and enlarged. For convex lenses, when the object is placed inside F, the image will be on the same side of the lens as the object and it will be virtual, upright, and enlarged.
- https://phys.libretexts.org/Courses/Fresno_City_College/NATSCI-1A%3A_Natural_Science_for_Educators_Fresno_City_College_(CID%3A_PHYS_140)/10%3A_Property_of_Sound_Doppler_Effect_and_Interferences/10.03%3A_Sound_WavesThe tree above generated sound waves when it fell to the ground, so it made sound according to the scientific definition. In longitudinal waves, particles of the medium vibrate back and forth parallel...The tree above generated sound waves when it fell to the ground, so it made sound according to the scientific definition. In longitudinal waves, particles of the medium vibrate back and forth parallel to the direction that the waves travel. Q: If there were no air particles to carry the vibrations away from the guitar string, how would sound reach the ear? That’s because the sound couldn’t travel away from the clock without air particles to pass the sound energy along.
- https://phys.libretexts.org/Courses/Fresno_City_College/NATSCI-1A%3A_Natural_Science_for_Educators_Fresno_City_College_(CID%3A_PHYS_140)/08%3A_Magnetism/8.05%3A_Electromagnetism/8.5.02%3A_Electromotive_ForceSince the charges are negative, the left hand rule shows that the electrons would move as diagrammed in the sketch. (Point fingers in the direction of the magnetic field, point thumb in the direction ...Since the charges are negative, the left hand rule shows that the electrons would move as diagrammed in the sketch. (Point fingers in the direction of the magnetic field, point thumb in the direction of wire movement, and palm shows direction of electron flow.) No current will flow, of course, unless the section of wire is part of a complete circuit.