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    • https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Physics_II_(2212)/01%3A_Introduction_to_Physics_Measurements_and_Mathematics_Tools/1.09%3A_Math_Review_of_Other_Topics/1.9.17%3A_Derivatives_and_the_Shape_of_a_Graph
      let f be a continuous function over an interval I containing a critical point c such that f is differentiable over I except possibly at c; if f changes sign from positive ...let f be a continuous function over an interval I containing a critical point c such that f is differentiable over I except possibly at c; if f changes sign from positive to negative as x increases through c, then f has a local maximum at c; if f changes sign from negative to positive as x increases through c, then f has a local minimum at c; if f does not change sign as x increases through c, then f does not hav…
    • https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Physics_I_(2211)/01%3A_Introduction_to_Physics_Measurements_and_Mathematics_Tools/1.09%3A_Math_Review_of_Other_Topics/1.9.23%3A_Physical_Applications_of_Integration
      In addition, instead of being concerned about the work done to move a single mass, we are looking at the work done to move a volume of water, and it takes more work to move the water from the bottom o...In addition, instead of being concerned about the work done to move a single mass, we are looking at the work done to move a volume of water, and it takes more work to move the water from the bottom of the tank than it does to move the water from the top of the tank. In pumping problems, the force required to lift the water to the top of the tank is the force required to overcome gravity, so it is equal to the weight of the water.
    • https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Physics_I_(2211)/01%3A_Introduction_to_Physics_Measurements_and_Mathematics_Tools/1.09%3A_Math_Review_of_Other_Topics/1.9.18%3A_Differentiation_Rules
      As we see in the following theorem, the derivative of the quotient is not the quotient of the derivatives; rather, it is the derivative of the function in the numerator times the function in the denom...As we see in the following theorem, the derivative of the quotient is not the quotient of the derivatives; rather, it is the derivative of the function in the numerator times the function in the denominator minus the derivative of the function in the denominator times the function in the numerator, all divided by the square of the function in the denominator.
    • https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Physics_I_(2211)/01%3A_Introduction_to_Physics_Measurements_and_Mathematics_Tools/1.09%3A_Math_Review_of_Other_Topics/1.9.22%3A_Anti-derivatives
      Therefore, every antiderivative of cosx is of the form sinx+C for some constant C and every function of the form sinx+C is an antiderivative of cosx. Therefore, every antid...Therefore, every antiderivative of cosx is of the form sinx+C for some constant C and every function of the form sinx+C is an antiderivative of cosx. Therefore, every antiderivative of ex is of the form ex+C for some constant C and every function of the form ex+C is an antiderivative of ex.
    • https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Physics_I_(2211)/01%3A_Introduction_to_Physics_Measurements_and_Mathematics_Tools/1.09%3A_Math_Review_of_Other_Topics/1.9.16%3A_The_Derivative_as_a_Function
      As we have seen, the derivative of a function at a given point gives us the rate of change or slope of the tangent line to the function at that point. The derivative function gives the derivative of a...As we have seen, the derivative of a function at a given point gives us the rate of change or slope of the tangent line to the function at that point. The derivative function gives the derivative of a function at each point in the domain of the original function for which the derivative is defined. To understand this notation better, recall that the derivative of a function at a point is the limit of the slopes of secant lines as the secant lines approach the tangent line.
    • https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Physics_II_(2212)/01%3A_Introduction_to_Physics_Measurements_and_Mathematics_Tools/1.09%3A_Math_Review_of_Other_Topics/1.9.25%3A_Table_of_Integrals
      39. unsinudu=uncosu+nun1cosudu 40. uncosudu=unsinunun1sinudu 41. \(\quad \begin{align*} \displaystyle ∫\sin^n u\co...39. unsinudu=uncosu+nun1cosudu 40. uncosudu=unsinunun1sinudu 41. sinnucosmudu=sinn1ucosm+1un+m+n1n+msinn2ucosmudu=sinn+1ucosm1un+m+m1n+msinnucosm2udu
    • https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Physics_I_(2211)/01%3A_Introduction_to_Physics_Measurements_and_Mathematics_Tools/1.09%3A_Math_Review_of_Other_Topics/1.9.14%3A_Exponential_and_Logarithmic_Functions
      \(\begin{array} {l c} {\text{Suppose we want to evaluate} \log_{a}M} & {\log_{a}M} \\ {\text{Let} \:y =\log_{a}M. }&{y=\log_{a}M} \\ {\text{Rewrite the epression in exponential form. }}&{a^{y}=M } \\ ...Suppose we want to evaluatelogaMlogaMLety=logaM.y=logaMRewrite the epression in exponential form. ay=MTake the logbof each side.logbay=logbMUse the Power Property.ylogba=logbMSolve fory.y=logbMlogbaSubstiturey=logaM.logaM=logbMlogba
    • https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Physics_I_(2211)/01%3A_Introduction_to_Physics_Measurements_and_Mathematics_Tools/1.09%3A_Math_Review_of_Other_Topics/1.9.25%3A_Table_of_Integrals
      39. unsinudu=uncosu+nun1cosudu 40. uncosudu=unsinunun1sinudu 41. \(\quad \begin{align*} \displaystyle ∫\sin^n u\co...39. unsinudu=uncosu+nun1cosudu 40. uncosudu=unsinunun1sinudu 41. sinnucosmudu=sinn1ucosm+1un+m+n1n+msinn2ucosmudu=sinn+1ucosm1un+m+m1n+msinnucosm2udu
    • https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Physics_II_(2212)/01%3A_Introduction_to_Physics_Measurements_and_Mathematics_Tools/1.09%3A_Math_Review_of_Other_Topics/1.9.14%3A_Exponential_and_Logarithmic_Functions
      \(\begin{array} {l c} {\text{Suppose we want to evaluate} \log_{a}M} & {\log_{a}M} \\ {\text{Let} \:y =\log_{a}M. }&{y=\log_{a}M} \\ {\text{Rewrite the epression in exponential form. }}&{a^{y}=M } \\ ...Suppose we want to evaluatelogaMlogaMLety=logaM.y=logaMRewrite the epression in exponential form. ay=MTake the logbof each side.logbay=logbMUse the Power Property.ylogba=logbMSolve fory.y=logbMlogbaSubstiturey=logaM.logaM=logbMlogba
    • https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Physics_II_(2212)/01%3A_Introduction_to_Physics_Measurements_and_Mathematics_Tools/1.09%3A_Math_Review_of_Other_Topics/1.9.18%3A_Differentiation_Rules
      As we see in the following theorem, the derivative of the quotient is not the quotient of the derivatives; rather, it is the derivative of the function in the numerator times the function in the denom...As we see in the following theorem, the derivative of the quotient is not the quotient of the derivatives; rather, it is the derivative of the function in the numerator times the function in the denominator minus the derivative of the function in the denominator times the function in the numerator, all divided by the square of the function in the denominator.
    • https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Introductory_Physics_II_(1112)/02%3A_Math_Review/2.08%3A_Functions
      Some students describe this function by stating that it “makes everything positive.” By the definition of the absolute value function, we see that if x<0, then |x|=x>0, and if x>0, then \...Some students describe this function by stating that it “makes everything positive.” By the definition of the absolute value function, we see that if x<0, then |x|=x>0, and if x>0, then |x|=x>0. However, for x=0, |x|=0. Therefore, it is more accurate to say that for all nonzero inputs, the output is positive, but if x=0, the output |x|=0.

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