By requiring solutions for ˜E and ˜H to satisfy the Maxwell curl equations (i.e., the Maxwell-Faraday equation and Ampere’s law), we find that \(\widetilde{\bf E}...By requiring solutions for ˜E and ˜H to satisfy the Maxwell curl equations (i.e., the Maxwell-Faraday equation and Ampere’s law), we find that ˜E, ˜H, and the direction of propagation ˆk are mutually perpendicular.
