By requiring solutions for \(\widetilde{\bf E}\) and \(\widetilde{\bf H}\) to satisfy the Maxwell curl equations (i.e., the Maxwell-Faraday equation and Ampere’s law), we find that \(\widetilde{\bf E}...By requiring solutions for \(\widetilde{\bf E}\) and \(\widetilde{\bf H}\) to satisfy the Maxwell curl equations (i.e., the Maxwell-Faraday equation and Ampere’s law), we find that \(\widetilde{\bf E}\), \(\widetilde{\bf H}\), and the direction of propagation \(\hat{\bf k}\) are mutually perpendicular.
