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    • https://phys.libretexts.org/Bookshelves/Electricity_and_Magnetism/Electromagnetics_I_(Ellingson)/03%3A_Transmission_Lines/3.06%3A_Wave_Equation_for_a_TEM_Transmission_Line
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    • https://phys.libretexts.org/Courses/Berea_College/Electromagnetics_I/03%3A_Transmission_Lines/3.06%3A_Wave_Equation_for_a_TEM_Transmission_Line
      We begin by differentiating both sides of Equation ??? with respect to z, yielding: \[-\frac{\partial^2}{\partial z^2} \widetilde{V}(z) = \left[ R' + j\omega L' \ri...We begin by differentiating both sides of Equation ??? with respect to z, yielding: 2z2˜V(z)=[R+jωL] z˜I(z) Then using Equation ??? to eliminate ˜I(z), we obtain \[-\frac{\partial^2}{\partial z^2} \widetilde{V}(z) = -\left[ R' + j\omega L' \right]\left[ G' + j\omega C' \right]~\widetilde{V}(z) \n…
    • https://phys.libretexts.org/Courses/Kettering_University/Electricity_and_Magnetism_with_Applications_to_Amateur_Radio_and_Wireless_Technology/21%3A_Electrical_Transmission_Lines/21.08%3A_Wave_Equation_for_a_Transmission_Line
      We begin by differentiating both sides of Equation ??? with respect to z, yielding: \[-\frac{\partial^2}{\partial z^2} \widetilde{V}(z) = \left[ R' + j\omega L' \ri...We begin by differentiating both sides of Equation ??? with respect to z, yielding: 2z2˜V(z)=[R+jωL] z˜I(z) Then using Equation ??? to eliminate ˜I(z), we obtain \[-\frac{\partial^2}{\partial z^2} \widetilde{V}(z) = -\left[ R' + j\omega L' \right]\left[ G' + j\omega C' \right]~\widetilde{V}(z) \n…

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