Loading [MathJax]/jax/output/SVG/config.js
Skip to main content
Library homepage
 

Text Color

Text Size

 

Margin Size

 

Font Type

Enable Dyslexic Font
Physics LibreTexts

Search

  • Filter Results
  • Location
  • Classification
    • Article type
    • Author
    • Embed Hypothes.is?
    • Embebbed CalcPlot3D?
    • Cover Page
    • License
    • Show TOC
    • Transcluded
    • OER program or Publisher
    • Student Analytics
    • Autonumber Section Headings
    • License Version
    • Print CSS
      • Screen CSS
      • PrintOptions
    • Include attachments
    Searching in
    About 3 results
    • https://phys.libretexts.org/Courses/Kettering_University/Electricity_and_Magnetism_with_Applications_to_Amateur_Radio_and_Wireless_Technology/18%3A_Calculation_of_Magnetic_Quantities_from_Currents/18.17%3A_Magnetic_Forces_and_Fields_(Answers)
      The magnitude of the proton and electron magnetic forces are the same since they have the same amount of charge. 43. \(\displaystyle A⋅m^2⋅T=A⋅m^2.\frac{N}{A⋅m}=N⋅m\) Since \(\displaystyle E=Blv\), wh...The magnitude of the proton and electron magnetic forces are the same since they have the same amount of charge. 43. \(\displaystyle A⋅m^2⋅T=A⋅m^2.\frac{N}{A⋅m}=N⋅m\) Since \(\displaystyle E=Blv\), where the width is twice the radius, \(\displaystyle I=2r,I=2r, I=nqAv_d\),\(\displaystyle v_d=\frac{I}{nqA}=\frac{I}{nqπr^2}\) so \(\displaystyle E=B×2r×\frac{I}{nqπr^2}=\frac{2IB}{nqπr}∝\frac{1}{r}∝\frac{1}{d}.\) The Hall voltage is inversely proportional to the diameter of the wire.
    • https://phys.libretexts.org/Courses/Muhlenberg_College/Physics_122%3A_General_Physics_II_(Collett)/07%3A_Magnetic_Forces_and_Fields/7.A%3A_Magnetic_Forces_and_Fields_(Answers)
      The magnitude of the proton and electron magnetic forces are the same since they have the same amount of charge. 43. \(\displaystyle A⋅m^2⋅T=A⋅m^2.\frac{N}{A⋅m}=N⋅m\) Since \(\displaystyle E=Blv\), wh...The magnitude of the proton and electron magnetic forces are the same since they have the same amount of charge. 43. \(\displaystyle A⋅m^2⋅T=A⋅m^2.\frac{N}{A⋅m}=N⋅m\) Since \(\displaystyle E=Blv\), where the width is twice the radius, \(\displaystyle I=2r,I=2r, I=nqAv_d\),\(\displaystyle v_d=\frac{I}{nqA}=\frac{I}{nqπr^2}\) so \(\displaystyle E=B×2r×\frac{I}{nqπr^2}=\frac{2IB}{nqπr}∝\frac{1}{r}∝\frac{1}{d}.\) The Hall voltage is inversely proportional to the diameter of the wire.
    • https://phys.libretexts.org/Courses/Kettering_University/Electricity_and_Magnetism_with_Applications_to_Amateur_Radio_and_Wireless_Technology/08%3A_The_Magnetic_Field/8.13%3A_Magnetic_Forces_and_Fields_(Answers)
      The magnitude of the proton and electron magnetic forces are the same since they have the same amount of charge. 43. \(\displaystyle A⋅m^2⋅T=A⋅m^2.\frac{N}{A⋅m}=N⋅m\) Since \(\displaystyle E=Blv\), wh...The magnitude of the proton and electron magnetic forces are the same since they have the same amount of charge. 43. \(\displaystyle A⋅m^2⋅T=A⋅m^2.\frac{N}{A⋅m}=N⋅m\) Since \(\displaystyle E=Blv\), where the width is twice the radius, \(\displaystyle I=2r,I=2r, I=nqAv_d\),\(\displaystyle v_d=\frac{I}{nqA}=\frac{I}{nqπr^2}\) so \(\displaystyle E=B×2r×\frac{I}{nqπr^2}=\frac{2IB}{nqπr}∝\frac{1}{r}∝\frac{1}{d}.\) The Hall voltage is inversely proportional to the diameter of the wire.

    Support Center

    How can we help?