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7.A: Nuclear Physics (Answers)
https://phys.libretexts.org/Courses/Bowdoin_College/Phys1140%3A_Introductory_Physics_II%3A_Part_2/07%3A__Nuclear_Physics/7.A%3A_Nuclear_Physics_(Answers)
Since $\displaystyle ^{238}U$ is a slowly decaying substance, only a very small number of nuclei decay on human timescales; therefore, although those nuclei that decay lose a noticeable fraction of ...Since $\displaystyle ^{238}U$ is a slowly decaying substance, only a very small number of nuclei decay on human timescales; therefore, although those nuclei that decay lose a noticeable fraction of their mass, the change in the total mass of the sample is not detectable for a macroscopic sample.
11.A: Nuclear Physics (Answers)
https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Physics_II_(2212)/11%3A__Nuclear_Physics/11.A%3A_Nuclear_Physics_(Answers)
Since $\displaystyle ^{238}U$ is a slowly decaying substance, only a very small number of nuclei decay on human timescales; therefore, although those nuclei that decay lose a noticeable fraction of ...Since $\displaystyle ^{238}U$ is a slowly decaying substance, only a very small number of nuclei decay on human timescales; therefore, although those nuclei that decay lose a noticeable fraction of their mass, the change in the total mass of the sample is not detectable for a macroscopic sample.
12.A: Nuclear Physics (Answers)
https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Introductory_Physics_II_(1112)/12%3A__Nuclear_Physics/12.A%3A_Nuclear_Physics_(Answers)
Since $\displaystyle ^{238}U$ is a slowly decaying substance, only a very small number of nuclei decay on human timescales; therefore, although those nuclei that decay lose a noticeable fraction of ...Since $\displaystyle ^{238}U$ is a slowly decaying substance, only a very small number of nuclei decay on human timescales; therefore, although those nuclei that decay lose a noticeable fraction of their mass, the change in the total mass of the sample is not detectable for a macroscopic sample.

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