Writing Newton’s Second Law in the vertical direction, for the case where only the weight acts on Barb or Kenny (mass m), when they are going at speed v \[\begin{aligned} mg &= ma_R = m\frac{v...Writing Newton’s Second Law in the vertical direction, for the case where only the weight acts on Barb or Kenny (mass m), when they are going at speed vmg=maR=mv2R∴ This corresponds to the minimum speed that they must have at the top of the loop to make it around.
Writing Newton’s Second Law in the vertical direction, for the case where only the weight acts on Barb or Kenny (mass m), when they are going at speed v \[\begin{aligned} mg &= ma_R = m\frac{v...Writing Newton’s Second Law in the vertical direction, for the case where only the weight acts on Barb or Kenny (mass m), when they are going at speed v\begin{aligned} mg &= ma_R = m\frac{v^2}{R}\\ \therefore v &= \sqrt{gR} = \sqrt{(9.8\text{m/s}^{2})(22\text{m})}=14.68\text{m/s}\end{aligned} This corresponds to the minimum speed that they must have at the top of the loop to make it around.
