The torque from each force about the hinge is given by: \[\begin{aligned} \vec \tau_M &= \vec r_M \times \vec F_g = \left(\frac{L}{2}\hat x\right) \times (-Mg \hat y) =-Mg\frac{L}{2} \hat z\\ \vec \ta...The torque from each force about the hinge is given by: →τM=→rM×→Fg=(L2ˆx)×(−Mgˆy)=−MgL2ˆz→τT=→rT×→T=(L3ˆx)×(−Tcosθˆx+Tsinθˆy)=TsinθL3ˆz→τm=→rm×→Fm=(Lˆx)×(−mgˆy)=−mgLˆz The sum of the torques in the z direction must b…
