Loading [MathJax]/jax/output/HTML-CSS/jax.js
Skip to main content
Library homepage
 

Text Color

Text Size

 

Margin Size

 

Font Type

Enable Dyslexic Font
Physics LibreTexts

Search

  • Filter Results
  • Location
  • Classification
    • Article type
    • Author
    • Cover Page
    • License
    • Show TOC
    • Transcluded
    • OER program or Publisher
    • Student Analytics
    • Autonumber Section Headings
    • License Version
    • Print CSS
      • Screen CSS
      • PrintOptions
    • Include attachments
    Searching in
    About 1 results
    • https://phys.libretexts.org/Courses/Berea_College/Introductory_Physics%3A_Berea_College/16%3A_Electric_Charges_and_Fields/16.07%3A_Sample_problems_and_solutions
      Thus, the field from one wire is given by: E=2kλRsin(π6)E=kλR Given that the charge Q is evenly distributed along...Thus, the field from one wire is given by: E=2kλRsin(π6)E=kλR Given that the charge Q is evenly distributed along the rod of length L, we can rewrite the charge density as QL, which gives: E=kQRL=kQL36L=6kQ3L2 This is the magnitude of the electric field for each side of the triangle.

    Support Center

    How can we help?