In order to determine the amount of energy released in each reaction, we need to determine the difference in mass between the two sides of the equation: \[\begin{aligned} 4p + 2e^- \to \alpha + 2\nu\e...In order to determine the amount of energy released in each reaction, we need to determine the difference in mass between the two sides of the equation: 4p+2e−→α+2ν On the left-hand side, the total mass is: MLHS=4mp+2me=4(938.3MeV/c2)+2(0.511MeV/c2)=3754.22MeV/c2 whereas on the right-hand side, the total mass is: \[\begin{aligned} M_{RHS}=m_\alpha=3727.4\text{MeV/c}^{2}\end{align…
