(Notice we have to be careful with the signs here - when moving to the right, the friction acts the other way!) Since the equilibrium moves to the right, the actual amplitude of this motion is (see th...(Notice we have to be careful with the signs here - when moving to the right, the friction acts the other way!) Since the equilibrium moves to the right, the actual amplitude of this motion is (see the figure) \(A_1=A-|x_0'|=A-\frac{\mu_k m g}{k}.\) Now when the block turns around, at the other maximum, during the leftward moving period the equilbrium changes again.
In Equation (11.2.14) we found that \(y_{0}^{\prime}-y_{0}=F_{e x t} / k\) for a spring of spring constant \(k\), where \(y_0\) was the old and \(y_{0}^{\prime}\) the new equilibrium position (the for...In Equation (11.2.14) we found that \(y_{0}^{\prime}-y_{0}=F_{e x t} / k\) for a spring of spring constant \(k\), where \(y_0\) was the old and \(y_{0}^{\prime}\) the new equilibrium position (the force was equal to \(−mg\); the displacement of the equilibrium position will be in the direction of the force).
