Suppose you drop a block of aluminum of mass 1 kg at a temperature of 80∘C in a liter of water (which also has a mass of 1 kg) at a temperature of 20∘C. The thermal energy given ...Suppose you drop a block of aluminum of mass 1 kg at a temperature of 80∘C in a liter of water (which also has a mass of 1 kg) at a temperature of 20∘C. The thermal energy given off by the aluminum equals ΔEAl=CAl(Tf−TAl) (this follows from the definition (13.2.1) of heat capacity; we could equally well call this quantity “the heat given off by the aluminum”).
