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- https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Physics_I_(2211)/10%3A_Momentum/10.09%3A_Angular_MomentumWe must include the Mars rock in the calculation of the moment of inertia, so we have ITotal=IR+IF+IMR=3.17kg⋅m2 and \[L = I \omega = (3.17\; kg\; \cdotp m^{2})(...We must include the Mars rock in the calculation of the moment of inertia, so we have ITotal=IR+IF+IMR=3.17kg⋅m2 and L=Iω=(3.17kg⋅m2)(0.1πrad/s)=0.32πkg⋅m2/s. Now the angular momentum vector is directed into the page in the −ˆk direction, by the right-hand rule, since the robot arm is now rotating clockwise.
- https://phys.libretexts.org/Courses/Muhlenberg_College/MC%3A_Physics_121_-_General_Physics_I/12%3A__Angular_Momentum/12.03%3A_Angular_MomentumThe angular momentum of a single particle about a designated origin is the vector product of the position vector in the given coordinate system and the particle’s linear momentum. The net torque on a ...The angular momentum of a single particle about a designated origin is the vector product of the position vector in the given coordinate system and the particle’s linear momentum. The net torque on a system about a given origin is the time derivative of the angular momentum about that origin. A rigid rotating body has angular momentum directed along the axis of rotation.
- https://phys.libretexts.org/Workbench/PH_245_Textbook_V2/04%3A_Module_3_-_Conservation_Laws/4.05%3A_Objective_3.e./4.5.01%3A_Angular_MomentumThe angular momentum of a single particle about a designated origin is the vector product of the position vector in the given coordinate system and the particle’s linear momentum. The net torque on a ...The angular momentum of a single particle about a designated origin is the vector product of the position vector in the given coordinate system and the particle’s linear momentum. The net torque on a system about a given origin is the time derivative of the angular momentum about that origin. A rigid rotating body has angular momentum directed along the axis of rotation.
