Loading [MathJax]/extensions/mml2jax.js
Skip to main content
Library homepage
 

Text Color

Text Size

 

Margin Size

 

Font Type

Enable Dyslexic Font
Physics LibreTexts

Search

  • Filter Results
  • Location
  • Classification
    • Article type
    • Author
    • Cover Page
    • License
    • Show TOC
    • Transcluded
    • OER program or Publisher
    • Student Analytics
    • Autonumber Section Headings
    • License Version
    • Print CSS
      • Screen CSS
      • PrintOptions
    • Include attachments
    Searching in
    About 2 results
    • 10.E: Practice
      https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Physics_I_(2211)/10%3A_Oscillations/10.E%3A_Practice
      The amplitude of the motion is the distance between the equilibrium position of the spring without the mass attached and the equilibrium position of the spring with the mass attached. (a) Show that th...The amplitude of the motion is the distance between the equilibrium position of the spring without the mass attached and the equilibrium position of the spring with the mass attached. (a) Show that the spring exerts an upward force of 2.00mg on the object at its lowest point. (b) If the spring has a force constant of 10.0 N/m, is hung horizontally, and the position of the free end of the spring is marked as y = 0.00 m, where is the new equilibrium position if a 0.25-kg-mass object is hung from …
    • 15.E: Oscillations (Exercises)
      https://phys.libretexts.org/Courses/Muhlenberg_College/Physics_122%3A_General_Physics_II_(Collett)/15%3A_Oscillations/15.E%3A_Oscillations_(Exercises)
      The amplitude of the motion is the distance between the equilibrium position of the spring without the mass attached and the equilibrium position of the spring with the mass attached. (a) Show that th...The amplitude of the motion is the distance between the equilibrium position of the spring without the mass attached and the equilibrium position of the spring with the mass attached. (a) Show that the spring exerts an upward force of 2.00mg on the object at its lowest point. (b) If the spring has a force constant of 10.0 N/m, is hung horizontally, and the position of the free end of the spring is marked as y = 0.00 m, where is the new equilibrium position if a 0.25-kg-mass object is hung from …

    Support Center

    How can we help?