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- https://phys.libretexts.org/Courses/Coalinga_College/Physical_Science_for_Educators_(CID%3A_PHYS_14)/10%3A_Forces/10.06%3A_Normal_Force_and_TensionThe arrows are approximately correct for when the elevator is accelerating upward—broken arrows represent forces too large to be drawn to scale. →T is the tension in the s...The arrows are approximately correct for when the elevator is accelerating upward—broken arrows represent forces too large to be drawn to scale. →T is the tension in the supporting cable, →w is the weight of the person, →ws is the weight of the scale, →we is the weight of the elevator, →Fs is the force of the scale o…
- https://phys.libretexts.org/Bookshelves/University_Physics/University_Physics_(OpenStax)/Book%3A_University_Physics_I_-_Mechanics_Sound_Oscillations_and_Waves_(OpenStax)/05%3A_Newton's_Laws_of_Motion/5.07%3A_Common_ForcesWhen an object rests on a nonaccelerating horizontal surface, the magnitude of the normal force is equal to the weight of the object. On an inclined plane, the weight of the object can be resolved int...When an object rests on a nonaccelerating horizontal surface, the magnitude of the normal force is equal to the weight of the object. On an inclined plane, the weight of the object can be resolved into components that act perpendicular and parallel to the surface of the plane. When a rope supports the weight of an object at rest, the tension in the rope is equal to the weight of the object. The force developed in a spring obeys Hooke’s law.
- https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Physics_I_(2211)/05%3A_Forces/5.03%3A_Common_Forces_-_Normal_(or_Perpendicular)_ForceFigure \PageIndex2: Since the acceleration is parallel to the slope and acting down the slope, it is most convenient to project all forces onto a coordinate system where one axis is parallel to ...Figure \PageIndex2: Since the acceleration is parallel to the slope and acting down the slope, it is most convenient to project all forces onto a coordinate system where one axis is parallel to the slope and the other is perpendicular to it (axes shown to the left of the skier). →FN is perpendicular to the slope and →Ff is parallel to the slope, but →Fg has components along both axes, namely, w y and w x . Here, →Fg has a squiggly line to show that …
- https://phys.libretexts.org/Bookshelves/University_Physics/University_Physics_I_-_Classical_Mechanics_(Gea-Banacloche)/06%3A_Interactions_II_-_Forces/6.03%3A_Forces_Not_Derived_From_a_Potential_EnergyThe price we pay for this simplification (and it is a simplification) is that we are left without an independent way to determine the value of the tension in any specific case; we just have to infer i...The price we pay for this simplification (and it is a simplification) is that we are left without an independent way to determine the value of the tension in any specific case; we just have to infer it from the acceleration of the object on which it acts (since it is a reaction force, it can assume any value as required to adjust to any circumstance—up to the point where the rope snaps, anyway).
- https://phys.libretexts.org/Courses/Tuskegee_University/Algebra_Based_Physics_I/04%3A_Dynamics-_Force_and_Newton's_Laws_of_Motion/4.06%3A_Normal%2C_Tension%2C_and_Other_Examples_of_ForcesForces are given many names, such as push, pull, thrust, lift, weight, friction, and tension. Traditionally, forces have been grouped into several categories and given names relating to their source, ...Forces are given many names, such as push, pull, thrust, lift, weight, friction, and tension. Traditionally, forces have been grouped into several categories and given names relating to their source, how they are transmitted, or their effects. The most important of these categories are discussed in this section, together with some interesting applications. Further examples of forces are discussed later in this text.
- https://phys.libretexts.org/Courses/Gettysburg_College/Gettysburg_College_Physics_for_Physics_Majors/22%3A_N8)_Forces_Energy_and_Work/22.03%3A_Forces_Not_Derived_From_a_Potential_EnergyThe price we pay for this simplification (and it is a simplification) is that we are left without an independent way to determine the value of the tension in any specific case; we just have to infer i...The price we pay for this simplification (and it is a simplification) is that we are left without an independent way to determine the value of the tension in any specific case; we just have to infer it from the acceleration of the object on which it acts (since it is a reaction force, it can assume any value as required to adjust to any circumstance—up to the point where the rope snaps, anyway).
- https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Physics_I_(2211)/05%3A_Forces/5.07%3A_Common_Forces_-_Stress_Strain_and_the_Spring_ForceThe pillar’s cross-sectional area is 0.20 m 2 and it is made of granite with a mass density of 2700 kg/m 3 . Find the compressive stress at the cross-section located 3.0 m below the top of the pillar ...The pillar’s cross-sectional area is 0.20 m 2 and it is made of granite with a mass density of 2700 kg/m 3 . Find the compressive stress at the cross-section located 3.0 m below the top of the pillar and the value of the compressive strain of the top 3.0-m segment of the pillar. Unlike in the previous example, however, if the weight of the rod is taken into consideration, the stress in the rod is largest at the top and smallest at the bottom of the rod where the equipment is attached.
- https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Physics_I_(2211)/05%3A_Forces/5.06%3A_Common_Forces_-_TensionFigure \PageIndex5: (a) Tendons in the finger carry force T from the muscles to other parts of the finger, usually changing the force’s direction but not its magnitude (the tendons are relativel...Figure \PageIndex5: (a) Tendons in the finger carry force T from the muscles to other parts of the finger, usually changing the force’s direction but not its magnitude (the tendons are relatively friction free). (b) The brake cable on a bicycle carries the tension T from the brake lever on the handlebars to the brake mechanism.
- https://phys.libretexts.org/Workbench/PH_245_Textbook_V2/03%3A_Module_2_-_Multi-Dimensional_Mechanics/3.03%3A_Objective_2.c./3.3.06%3A_Common_ForcesWhen an object rests on a nonaccelerating horizontal surface, the magnitude of the normal force is equal to the weight of the object. On an inclined plane, the weight of the object can be resolved int...When an object rests on a nonaccelerating horizontal surface, the magnitude of the normal force is equal to the weight of the object. On an inclined plane, the weight of the object can be resolved into components that act perpendicular and parallel to the surface of the plane. When a rope supports the weight of an object at rest, the tension in the rope is equal to the weight of the object. The force developed in a spring obeys Hooke’s law.
- https://phys.libretexts.org/Courses/Joliet_Junior_College/Physics_201_-_Fall_2019/Book%3A_Physics_(Boundless)/05%3A_The_Laws_of_Motion/5.14%3A_Common_ForcesWhen an object rests on a nonaccelerating horizontal surface, the magnitude of the normal force is equal to the weight of the object. On an inclined plane, the weight of the object can be resolved int...When an object rests on a nonaccelerating horizontal surface, the magnitude of the normal force is equal to the weight of the object. On an inclined plane, the weight of the object can be resolved into components that act perpendicular and parallel to the surface of the plane. When a rope supports the weight of an object at rest, the tension in the rope is equal to the weight of the object. The force developed in a spring obeys Hooke’s law.
- https://phys.libretexts.org/Courses/Muhlenberg_College/MC%3A_Physics_121_-_General_Physics_I/06%3A_Newton's_Laws_of_Motion/6.07%3A_Common_ForcesWhen an object rests on a nonaccelerating horizontal surface, the magnitude of the normal force is equal to the weight of the object. On an inclined plane, the weight of the object can be resolved int...When an object rests on a nonaccelerating horizontal surface, the magnitude of the normal force is equal to the weight of the object. On an inclined plane, the weight of the object can be resolved into components that act perpendicular and parallel to the surface of the plane. When a rope supports the weight of an object at rest, the tension in the rope is equal to the weight of the object. The force developed in a spring obeys Hooke’s law.