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    About 7 results
    • https://phys.libretexts.org/Bookshelves/Nuclear_and_Particle_Physics/Nuclear_and_Particle_Physics_(Walet)/04%3A_Nuclear_Models/4.04%3A_Barrier_Penetration
      To understand quantum mechanical tunnelling in fission it makes sense to look at the simplest fission process: the emission of a He nucleus, so called α radiation
    • https://phys.libretexts.org/Bookshelves/University_Physics/Physics_(Boundless)/30%3A_Nuclear_Physics_and_Radioactivity/30.3%3A_Quantum_Tunneling_and_Conservation_Laws
      If an object lacks enough energy to pass through a barrier, it is possible for it to “tunnel” through imaginary space to the other side.
    • https://phys.libretexts.org/Bookshelves/Quantum_Mechanics/Quantum_Mechanics_(Fowler)/03%3A_Mostly_1-D_Quantum_Mechanics/3.01%3A_1-D_Schrodinger_Equation_-_Example_Systems
      Rather, the lowest energy state must have the minimal amount of bending of the wavefunction necessary for it to be zero at both walls but nonzero in between -- this corresponds to half a period of a s...Rather, the lowest energy state must have the minimal amount of bending of the wavefunction necessary for it to be zero at both walls but nonzero in between -- this corresponds to half a period of a sine or cosine (depending on the choice of origin), these functions being the solutions of Schrödinger’s equation in the zero potential region between the walls.
    • https://phys.libretexts.org/Bookshelves/Modern_Physics/Spiral_Modern_Physics_(D'Alessandris)/6%3A_The_Schrodinger_Equation/6.7%3A_Barrier_Penetration_and_Tunneling
      First, notice that the probability of tunneling out of the well is exactly equal to the probability of tunneling in, since all of the parameters of the barrier are exactly the same. Remember, T is now...First, notice that the probability of tunneling out of the well is exactly equal to the probability of tunneling in, since all of the parameters of the barrier are exactly the same. Remember, T is now the probability of escape per collision with a well wall, so the inverse of T must be the number of collisions needed, on average, to escape. If we can determine the number of seconds between collisions, the product of this number and the inverse of T should be the lifetime () of the state:
    • https://phys.libretexts.org/Courses/Prince_Georges_Community_College/PHY_2040%3A_General_Physics_III/10%3A_Nuclear_Physics_and_Radioactivity/10.3%3A_Quantum_Tunneling_and_Conservation_Laws
      If an object lacks enough energy to pass through a barrier, it is possible for it to “tunnel” through imaginary space to the other side.
    • https://phys.libretexts.org/Courses/Muhlenberg_College/MC_%3A_Physics_213_-_Modern_Physics/05%3A_The_Schrodinger_Equation/5.07%3A_Barrier_Penetration_and_Tunneling
      First, notice that the probability of tunneling out of the well is exactly equal to the probability of tunneling in, since all of the parameters of the barrier are exactly the same. Remember, T is now...First, notice that the probability of tunneling out of the well is exactly equal to the probability of tunneling in, since all of the parameters of the barrier are exactly the same. Remember, T is now the probability of escape per collision with a well wall, so the inverse of T must be the number of collisions needed, on average, to escape. If we can determine the number of seconds between collisions, the product of this number and the inverse of T should be the lifetime () of the state:
    • https://phys.libretexts.org/Bookshelves/College_Physics/College_Physics_1e_(OpenStax)/31%3A_Radioactivity_and_Nuclear_Physics/31.07%3A_Tunneling
      Protons and neutrons are bound inside nuclei, that means energy must be supplied to break them away.

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