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- https://phys.libretexts.org/Courses/Coalinga_College/Physical_Science_for_Educators_(CID%3A_PHYS_14)/09%3A_Motion/9.03%3A_Motion_in_One-Dimension/9.3.06%3A_Uniform_Acceleration(a) This car is speeding up as it moves toward the right (positive x-direction), so it has positive acceleration in our coordinate system. (b) This car is slowing down as it moves toward the right, so...(a) This car is speeding up as it moves toward the right (positive x-direction), so it has positive acceleration in our coordinate system. (b) This car is slowing down as it moves toward the right, so it has negative acceleration in our coordinate system because the acceleration is toward the left (negative x-direction).
- https://phys.libretexts.org/Bookshelves/College_Physics/Supplemental_Modules_(College_Physics)/Introductory_Kinematics/03%3A_Circular_Motion/3.01%3A_Uniform_Circular_Motion_and_Analogy_to_Linear_MotionAngular acceleration is the rate of change of angular velocity, and angular velocity is the rate of change of angular displacement. In short, any angular quantity is the same as its linear quantity, e...Angular acceleration is the rate of change of angular velocity, and angular velocity is the rate of change of angular displacement. In short, any angular quantity is the same as its linear quantity, except it describes the angle between the axis of rotation and the position of object, rather than the distance-based quantities. This is actually a pseudovector and is the result of taking the cross-product (this is out of scope of this book) of the radius of rotation and the angular quantity.
- https://phys.libretexts.org/Bookshelves/College_Physics/Supplemental_Modules_(College_Physics)/Introductory_Kinematics/02%3A_Linear_Motion_and_its_Various_Forms/2.01%3A_Uniform_Linear_MotionHowever, it is important to note that displacement only gives the distance from the initial and final position, not the length of the whole path as distance would. Though the distance you covered woul...However, it is important to note that displacement only gives the distance from the initial and final position, not the length of the whole path as distance would. Though the distance you covered would be 2m, because your initial and final position are the same, your displacement is 0. By convention, a little arrow is put on the top of a vector value, or the character is bold (e.g. In the graph, this corresponds to the area between the x-axis and the line denoting the velocity.