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1.15: A= π B

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There are several occasions in radiation theory in which one quantity is equal to π times another, the two quantities being related by an equation of the form A=πB. I can think of three, and they are all related to the three questions asked and answered in section 1.14.

If the source in question i of Section 1.14 is an element of a lambertian surface, then I(θ,ϕ) is given by Equation 1.13.1, and in that case Equation 1.14.1 becomes

ϕ=πI(0)

If the element δ A in question ii is lambertian, L is independent of θ and f , and equation 1.14.3 becomes

M=πL

This, then is the very important relation between the exitance and the radiance of a lambertian surface. It is easy to remember which way round it is if you think of the units in which M and L are expressed and think of π as a solid angle.

If the hemisphere of question iii is uniformly lambertian (for example, if the sky is uniformly dull and cloudy) then L is the same everywhere in the sky, and the irradiance is

E=πL


This page titled 1.15: A= π B is shared under a CC BY-NC 4.0 license and was authored, remixed, and/or curated by Jeremy Tatum via source content that was edited to the style and standards of the LibreTexts platform.

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