4.12: Center of Mass
( \newcommand{\kernel}{\mathrm{null}\,}\)
If an inertial frame of reference K′ is moving at constant velocity →V relative to inertial frame K, the velocities of individual particles in the frames are related by →vi=→v′i+→V, so the total momenta are related by
→P=∑imi→vi=∑imi→v′i+→V∑imi=→P′+M→V,M=∑imi
If we choose →V=→P/M, then →P′=∑imi→v′i=0, the system is “at rest” in the frame K′. Of course, the individual particles might be moving, what is at rest in ¯K′ is the center of mass defined by
M→Rcm=∑imi→ri
(Check this by differentiating both sides with respect to time.)
The energy of a mechanical system in its rest frame is often called its internal energy, we’ll denote it by Eint (This includes kinetic and potential energies.) The total energy of a moving system is then
E=12M→V2+Eint
(Exercise: verify this.)