Loading [MathJax]/jax/output/HTML-CSS/jax.js
Skip to main content
Library homepage
 

Text Color

Text Size

 

Margin Size

 

Font Type

Enable Dyslexic Font
Physics LibreTexts

3.8: Eigenstates and Eigenvalues

( \newcommand{\kernel}{\mathrm{null}\,}\)

Consider a general real-space operator, A(x). When this operator acts on a general wavefunction ψ(x) the result is usually a wavefunction with a completely different shape. However, there are certain special wavefunctions which are such that when A acts on them the result is just a multiple of the original wavefunction. These special wavefunctions are called eigenstates, and the multiples are called eigenvalues. Thus, if Aψa(x)=aψa(x), where a is a complex number, then ψa is called an eigenstate of A corresponding to the eigenvalue a.

Suppose that A is an Hermitian operator corresponding to some physical dynamical variable. Consider a particle whose wavefunction is ψa. The expectation of value A in this state is simply [see Equation ([e3.55])] A=ψaAψadx=aψaψadx=a, where use has been made of Equation ([e3.107]) and the normalization condition ([e3.4]). Moreover, A2=ψaA2ψadx=aψaAψadx=a2ψaψadx=a2, so the variance of A is [cf., Equation ([e3.24a])] σ2A=A2A2=a2a2=0. The fact that the variance is zero implies that every measurement of A is bound to yield the same result: namely, a. Thus, the eigenstate ψa is a state that is associated with a unique value of the dynamical variable corresponding to A. This unique value is simply the associated eigenvalue.

It is easily demonstrated that the eigenvalues of an Hermitian operator are all real. Recall [from Equation ([e3.84])] that an Hermitian operator satisfies ψ1(Aψ2)dx=(Aψ1)ψ2dx. Hence, if ψ1=ψ2=ψa then ψa(Aψa)dx=(Aψa)ψadx, which reduces to [see Equation ([e3.107])] a=a, assuming that ψa is properly normalized.

Two wavefunctions, ψ1(x) and ψ2(x), are said to be orthogonal if ψ1ψ2dx=0. Consider two eigenstates of A, ψa and ψa, which correspond to the two different eigenvalues a and a, respectively. Thus, Aψa=aψa,Aψa=aψa. Multiplying the complex conjugate of the first equation by ψa, and the second equation by ψa, and then integrating over all x, we obtain (Aψa)ψadx=aψaψadx,ψa(Aψa)dx=aψaψadx. However, from Equation ([e3.111]), the left-hand sides of the previous two equations are equal. Hence, we can write (aa)ψaψadx=0. By assumption, aa, yielding ψaψadx=0. In other words, eigenstates of an Hermitian operator corresponding to different eigenvalues are automatically orthogonal.

Consider two eigenstates of A, ψa and ψa, that correspond to the same eigenvalue, a. Such eigenstates are termed degenerate. The previous proof of the orthogonality of different eigenstates fails for degenerate eigenstates. Note, however, that any linear combination of ψa and ψa is also an eigenstate of A corresponding to the eigenvalue a. Thus, even if ψa and ψa are not orthogonal, we can always choose two linear combinations of these eigenstates that are orthogonal. For instance, if ψa and ψa are properly normalized, and ψaψadx=c, then it is easily demonstrated that ψa=|c|1|c|2(ψac1ψa) is a properly normalized eigenstate of A, corresponding to the eigenvalue a, that is orthogonal to ψa. It is straightforward to generalize the previous argument to three or more degenerate eigenstates. Hence, we conclude that the eigenstates of an Hermitian operator are, or can be chosen to be, mutually orthogonal.

It is also possible to demonstrate that the eigenstates of an Hermitian operator form a complete set : that is, any general wavefunction can be written as a linear combination of these eigenstates. However, the proof is quite difficult, and we shall not attempt it here.

In summary, given an Hermitian operator A, any general wavefunction, ψ(x), can be written ψ=iciψi, where the ci are complex weights, and the ψi are the properly normalized (and mutually orthogonal) eigenstates of A: that is, Aψi=aiψi, where ai is the eigenvalue corresponding to the eigenstate ψi, and ψiψjdx=δij. Here, δij is called the Kronecker delta-function , and takes the value unity when its two indices are equal, and zero otherwise.

It follows from Equations ([e3.123]) and ([e3.125]) that ci=ψiψdx. Thus, the expansion coefficients in Equation ([e3.123]) are easily determined, given the wavefunction ψ and the eigenstates ψi. Moreover, if ψ is a properly normalized wavefunction then Equations ([e3.123]) and ([e3.125]) yield i|ci|2=1.

Contributors and Attributions

  • Richard Fitzpatrick (Professor of Physics, The University of Texas at Austin)


This page titled 3.8: Eigenstates and Eigenvalues is shared under a not declared license and was authored, remixed, and/or curated by Richard Fitzpatrick.

Support Center

How can we help?