The forces on mass \(m_{1}\) are the upward tension \(T\) as before, plus a downward acceleration \(m_{1} g \sin \theta\) down the inclined plane. In this case, mass \(m_{1}\) will experience an upslo...The forces on mass \(m_{1}\) are the upward tension \(T\) as before, plus a downward acceleration \(m_{1} g \sin \theta\) down the inclined plane. In this case, mass \(m_{1}\) will experience an upslope force equal to the tension \(T\) and a downslope force \(m_{1} g \sin \theta\). \[\Sigma_{i} F_{i}=m_{1} a \quad \Rightarrow \quad T-m_{1} g \sin \theta-\mu m_{1} g \cos \theta=m_{1} a\] \[a=\frac{m_{2}-m_{1}(\mu \cos \theta+\sin \theta)}{m_{1}+m_{2}} g\]
