The rather disconcerting factor K(T), which does not depend on \omega and hence has nothing to do with the dy_n amics, can be thrown in with similar time-dependent and constant factors involved in the...The rather disconcerting factor K(T), which does not depend on \omega and hence has nothing to do with the dy_n amics, can be thrown in with similar time-dependent and constant factors involved in the measure of the integral over paths, and their overall contribution can be nailed down by the simple observation that for \omega =0, we must recover the known free-particle propagator.
In quantum mechanics, such as the motion of an electron in an atom, we know that the particle does not follow a well-defined path, in contrast to classical mechanics. Where does the crossover to a wel...In quantum mechanics, such as the motion of an electron in an atom, we know that the particle does not follow a well-defined path, in contrast to classical mechanics. Where does the crossover to a well-defined path take place? Feynman (in Feynman and Hibbs) gives a nice picture to help think about summing over paths.
