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8.6: Kinetic Energy and the Work-Energy Theorem
https://phys.libretexts.org/Courses/Coalinga_College/Physical_Science_for_Educators_(CID%3A_PHYS_14)/08%3A_Energy_Physics_and_Chemistry/8.06%3A_Kinetic_Energy_and_the_Work-Energy_Theorem
The net work $W_{net}$ is the work done by the net force acting on an object. Work done on an object transfers energy to the object. The translational kinetic energy of an object of mass $m$ movin...The net work $W_{net}$ is the work done by the net force acting on an object. Work done on an object transfers energy to the object. The translational kinetic energy of an object of mass $m$ moving at speed $v$ is $KE = \frac{1}{2}mv^2$ . The work-energy theorem states that the net work $W_{net}$ on a system changes its kinetic energy, $W_{net} = \frac{1}{2}mv^2 - \frac{1}{2}mv_0^2$ .
7.2: Kinetic Energy and the Work-Energy Theorem
https://phys.libretexts.org/Bookshelves/College_Physics/College_Physics_1e_(OpenStax)/07%3A_Work_Energy_and_Energy_Resources/7.02%3A_Kinetic_Energy_and_the_Work-Energy_Theorem
The net work $W_{net}$ is the work done by the net force acting on an object. Work done on an object transfers energy to the object. The translational kinetic energy of an object of mass $m$ movin...The net work $W_{net}$ is the work done by the net force acting on an object. Work done on an object transfers energy to the object. The translational kinetic energy of an object of mass $m$ moving at speed $v$ is $KE = \frac{1}{2}mv^2$ . The work-energy theorem states that the net work $W_{net}$ on a system changes its kinetic energy, $W_{net} = \frac{1}{2}mv^2 - \frac{1}{2}mv_0^2$ .
8.4: Work-Energy Theorem
https://phys.libretexts.org/Courses/Muhlenberg_College/MC%3A_Physics_121_-_General_Physics_I/08%3A_Work_and_Kinetic_Energy/8.04%3A_Work-Energy_Theorem
Work-Energy Theorem argues the net work done on a particle equals the change in the particle’s kinetic energy. According to this theorem, when an object slows down, its final kinetic energy is less th...Work-Energy Theorem argues the net work done on a particle equals the change in the particle’s kinetic energy. According to this theorem, when an object slows down, its final kinetic energy is less than its initial kinetic energy, the change in its kinetic energy is negative, and so is the net work done on it. If an object speeds up, the net work done on it is positive.
13.6: Work-Kinetic Energy Theorem
https://phys.libretexts.org/Bookshelves/Classical_Mechanics/Classical_Mechanics_(Dourmashkin)/13%3A_Energy_Kinetic_Energy_and_Work/13.06%3A_Work-Kinetic_Energy_Theorem
For an object undergoing one-dimensional motion the left hand side of Equation (13.3.16) is the work done on the object by the component of the sum of the forces in the direction of displacement, The ...For an object undergoing one-dimensional motion the left hand side of Equation (13.3.16) is the work done on the object by the component of the sum of the forces in the direction of displacement, The total work done on the cup is the sum of the work done by the pushing force and the work done by the friction force, as given in Equations (13.4.9) and (13.4.14),
3.3: Kinetic Energy and the Work-Energy Theorem
https://phys.libretexts.org/Courses/Skyline/Survey_of_Physics/03%3A_Work_and_Energy/3.03%3A_Kinetic_Energy_and_the_Work-Energy_Theorem
The net work $W_{net}$ is the work done by the net force acting on an object. Work done on an object transfers energy to the object. The translational kinetic energy of an object of mass $m$ movin...The net work $W_{net}$ is the work done by the net force acting on an object. Work done on an object transfers energy to the object. The translational kinetic energy of an object of mass $m$ moving at speed $v$ is $KE = \frac{1}{2}mv^2$ . The work-energy theorem states that the net work $W_{net}$ on a system changes its kinetic energy, $W_{net} = \frac{1}{2}mv^2 - \frac{1}{2}mv_0^2$ .
10.2: Work on a Single Particle
https://phys.libretexts.org/Courses/Merrimack_College/Conservation_Laws_Newton's_Laws_and_Kinematics_version_2.0/10%3A_C10)_Work/10.02%3A_Work_on_a_Single_Particle
You can also see this directly from Equation ( $\ref{eq:7.5}$ ), by choosing the $x$ axis to point in the direction of the force (so $F_y$ = $F_z$ = 0), and the displacement to point along any of th...You can also see this directly from Equation ( $\ref{eq:7.5}$ ), by choosing the $x$ axis to point in the direction of the force (so $F_y$ = $F_z$ = 0), and the displacement to point along any of the other two axes (so $\Delta x$ = 0): the result is $W$ = 0. So—for this very simple system—we could rephrase the result ( $\ref{eq:7.11}$ ) by saying that the work done by the net external force acting on the system (the particle in this case) is equal to the change in its total energy.
26.6: The Virial Theorem
https://phys.libretexts.org/Courses/Prince_Georges_Community_College/General_Physics_I%3A_Classical_Mechanics/26%3A_Energy/26.06%3A_The_Virial_Theorem
Since the total energy $E=\langle K\rangle+\langle U\rangle$ , we can use the virial theorem (Eq. $\PageIndex{2}$ ) to derive a useful expression for the total energy in terms of the time-average en...Since the total energy $E=\langle K\rangle+\langle U\rangle$ , we can use the virial theorem (Eq. $\PageIndex{2}$ ) to derive a useful expression for the total energy in terms of the time-average energies: By the virial theorem, the second example shows that the increase in potential energy is twice the decrease in potential energy, so overall, the total energy is increased for higher orbits.
7.4: Work-Energy Theorem
https://phys.libretexts.org/Bookshelves/University_Physics/University_Physics_(OpenStax)/Book%3A_University_Physics_I_-_Mechanics_Sound_Oscillations_and_Waves_(OpenStax)/07%3A_Work_and_Kinetic_Energy/7.04%3A_Work-Energy_Theorem
Work-Energy Theorem argues the net work done on a particle equals the change in the particle’s kinetic energy. According to this theorem, when an object slows down, its final kinetic energy is less th...Work-Energy Theorem argues the net work done on a particle equals the change in the particle’s kinetic energy. According to this theorem, when an object slows down, its final kinetic energy is less than its initial kinetic energy, the change in its kinetic energy is negative, and so is the net work done on it. If an object speeds up, the net work done on it is positive.
7.4: Work-Energy Theorem
https://phys.libretexts.org/Courses/Joliet_Junior_College/Physics_201_-_Fall_2019/Book%3A_Physics_(Boundless)/07%3A_Work_and_Energy/7.04%3A_Work-Energy_Theorem
Work-Energy Theorem argues the net work done on a particle equals the change in the particle’s kinetic energy. According to this theorem, when an object slows down, its final kinetic energy is less th...Work-Energy Theorem argues the net work done on a particle equals the change in the particle’s kinetic energy. According to this theorem, when an object slows down, its final kinetic energy is less than its initial kinetic energy, the change in its kinetic energy is negative, and so is the net work done on it. If an object speeds up, the net work done on it is positive.
21.4: Examples
https://phys.libretexts.org/Courses/Merrimack_College/Conservation_Laws_Newton's_Laws_and_Kinematics_version_2.0/21%3A_N8)_Forces_Energy_and_Work/21.04%3A_Examples
Work-Energy Theorem argues the net work done on a particle equals the change in the particle’s kinetic energy. According to this theorem, when an object slows down, its final kinetic energy is less th...Work-Energy Theorem argues the net work done on a particle equals the change in the particle’s kinetic energy. According to this theorem, when an object slows down, its final kinetic energy is less than its initial kinetic energy, the change in its kinetic energy is negative, and so is the net work done on it. If an object speeds up, the net work done on it is positive.
3.2: Kinetic Energy
https://phys.libretexts.org/Bookshelves/University_Physics/Mechanics_and_Relativity_(Idema)/03%3A_Energy/3.02%3A_Kinetic_Energy
If you want to start moving something that is initially at rest, you’ll need to accelerate it, and Newton’s second law tells you that this requires a force - and moving something means that you’re dis...If you want to start moving something that is initially at rest, you’ll need to accelerate it, and Newton’s second law tells you that this requires a force - and moving something means that you’re displacing it. Therefore, there is work involved in getting something moving. We define the kinetic energy (K) of a moving object to be equal to the work required to bring the object from rest to that speed, or equivalently, from that speed to rest.

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