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- https://phys.libretexts.org/Bookshelves/Classical_Mechanics/Graduate_Classical_Mechanics_(Fowler)/16%3A_Elastic_Scattering/16.03%3A_The_Differential_Cross_SectionThe differential cross section, written dσ/dΩ is the fraction of the total number of scattered particles that come out in the solid angle dΩ, so the rate of particle scatte...The differential cross section, written dσ/dΩ is the fraction of the total number of scattered particles that come out in the solid angle dΩ, so the rate of particle scattering to this detector is ndσ/dΩ, with n the beam intensity as defined above.
- https://phys.libretexts.org/Bookshelves/Quantum_Mechanics/Quantum_Mechanics_(Fowler)/10%3A_Scattering_Theory/10.01%3A_Scattering_TheoryThe simplest model of a scattering experiment is given by solving Schrödinger’s equation for a plane wave impinging on a localized potential. A potential V(r) might represent what a fast electron enc...The simplest model of a scattering experiment is given by solving Schrödinger’s equation for a plane wave impinging on a localized potential. A potential V(r) might represent what a fast electron encounters on striking an atom, or an alpha particle a nucleus. Obviously, representing any such system by a potential is only a beginning, but in certain energy ranges it is quite reasonable, and we have to start somewhere!
- https://phys.libretexts.org/Bookshelves/Nuclear_and_Particle_Physics/Introduction_to_Applied_Nuclear_Physics_(Cappellaro)/08%3A_Applications_of_Nuclear_Science_(PDF_-_1.4MB)/8.01%3A_Interaction_of_Radiation_with_MatterHere Λ′ is now a different ratio than the one obtained for the alpha particles, but with a similar meaning: \(\Lambda^{\prime} = \sqrt{\frac{T}{2 m_{e} v^{2}}} \frac{\left(T+m c^{2}...Here Λ′ is now a different ratio than the one obtained for the alpha particles, but with a similar meaning: Λ′=√T2mev2(T+mc2)EI, where again we can recognize the ratio of the electron energy (determining the minimum distance) and the mean excitation energy EI (which sets the maximum distance) as well as a correction due to relativistic effects.
