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    • https://phys.libretexts.org/Courses/Muhlenberg_College/MC%3A_Physics_121_-_General_Physics_I/10%3A_Linear_Momentum_and_Collisions/10.07%3A_Types_of_Collisions
      An elastic collision is one that conserves kinetic energy. An inelastic collision does not conserve kinetic energy. Momentum is conserved regardless of whether or not kinetic energy is conserved. Anal...An elastic collision is one that conserves kinetic energy. An inelastic collision does not conserve kinetic energy. Momentum is conserved regardless of whether or not kinetic energy is conserved. Analysis of kinetic energy changes and conservation of momentum together allow the final velocities to be calculated in terms of initial velocities and masses in one-dimensional, two-body collisions.
    • https://phys.libretexts.org/Courses/Joliet_Junior_College/Physics_201_-_Fall_2019/Book%3A_Physics_(Boundless)/08%3A_Linear_Momentum_and_Collisions/8.07%3A_Types_of_Collisions
      An elastic collision is one that conserves kinetic energy. An inelastic collision does not conserve kinetic energy. Momentum is conserved regardless of whether or not kinetic energy is conserved. Anal...An elastic collision is one that conserves kinetic energy. An inelastic collision does not conserve kinetic energy. Momentum is conserved regardless of whether or not kinetic energy is conserved. Analysis of kinetic energy changes and conservation of momentum together allow the final velocities to be calculated in terms of initial velocities and masses in one-dimensional, two-body collisions.
    • https://phys.libretexts.org/Courses/Joliet_Junior_College/Physics_201_-_Fall_2019v2/Book%3A_Custom_Physics_textbook_for_JJC/09%3A_Linear_Momentum_and_Collisions/9.07%3A_Types_of_Collisions
      An elastic collision is one that conserves kinetic energy. An inelastic collision does not conserve kinetic energy. Momentum is conserved regardless of whether or not kinetic energy is conserved. Anal...An elastic collision is one that conserves kinetic energy. An inelastic collision does not conserve kinetic energy. Momentum is conserved regardless of whether or not kinetic energy is conserved. Analysis of kinetic energy changes and conservation of momentum together allow the final velocities to be calculated in terms of initial velocities and masses in one-dimensional, two-body collisions.
    • https://phys.libretexts.org/Courses/Gettysburg_College/Gettysburg_College_Physics_for_Physics_Majors/14%3A_C14)_Collisions/14.01%3A_Types_of_Collisions
      An elastic collision is one that conserves kinetic energy. An inelastic collision does not conserve kinetic energy. Momentum is conserved regardless of whether or not kinetic energy is conserved. Anal...An elastic collision is one that conserves kinetic energy. An inelastic collision does not conserve kinetic energy. Momentum is conserved regardless of whether or not kinetic energy is conserved. Analysis of kinetic energy changes and conservation of momentum together allow the final velocities to be calculated in terms of initial velocities and masses in one-dimensional, two-body collisions.
    • https://phys.libretexts.org/Courses/Merrimack_College/Conservation_Laws_Newton's_Laws_and_Kinematics_version_2.0/12%3A_C12)_Collisions/12.01%3A_Types_of_Collisions
      An elastic collision is one that conserves kinetic energy. An inelastic collision does not conserve kinetic energy. Momentum is conserved regardless of whether or not kinetic energy is conserved. Anal...An elastic collision is one that conserves kinetic energy. An inelastic collision does not conserve kinetic energy. Momentum is conserved regardless of whether or not kinetic energy is conserved. Analysis of kinetic energy changes and conservation of momentum together allow the final velocities to be calculated in terms of initial velocities and masses in one-dimensional, two-body collisions.
    • https://phys.libretexts.org/Workbench/PH_245_Textbook_V2/04%3A_Module_3_-_Conservation_Laws/4.04%3A_Objective_3.d./4.4.03%3A_Types_of_Collisions
      An elastic collision is one that conserves kinetic energy. An inelastic collision does not conserve kinetic energy. Momentum is conserved regardless of whether or not kinetic energy is conserved. Anal...An elastic collision is one that conserves kinetic energy. An inelastic collision does not conserve kinetic energy. Momentum is conserved regardless of whether or not kinetic energy is conserved. Analysis of kinetic energy changes and conservation of momentum together allow the final velocities to be calculated in terms of initial velocities and masses in one-dimensional, two-body collisions.
    • https://phys.libretexts.org/Bookshelves/University_Physics/University_Physics_(OpenStax)/Book%3A_University_Physics_I_-_Mechanics_Sound_Oscillations_and_Waves_(OpenStax)/09%3A_Linear_Momentum_and_Collisions/9.07%3A_Types_of_Collisions
      An elastic collision is one that conserves kinetic energy. An inelastic collision does not conserve kinetic energy. Momentum is conserved regardless of whether or not kinetic energy is conserved. Anal...An elastic collision is one that conserves kinetic energy. An inelastic collision does not conserve kinetic energy. Momentum is conserved regardless of whether or not kinetic energy is conserved. Analysis of kinetic energy changes and conservation of momentum together allow the final velocities to be calculated in terms of initial velocities and masses in one-dimensional, two-body collisions.
    • https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Physics_I_(2211)/10%3A_Momentum/10.04%3A_Types_of_Collisions
      The initial kinetic energy of the system, like the initial momentum, is all in the hammer: $\begin{split} K_{i} & = \frac{1}{2} M_{H} v_{H}^{2} \\ & = \frac{1}{2} (70\; kg)(10\; m/s)^{2} \\ & = 3500\;...The initial kinetic energy of the system, like the initial momentum, is all in the hammer: $\begin{split} K_{i} & = \frac{1}{2} M_{H} v_{H}^{2} \\ & = \frac{1}{2} (70\; kg)(10\; m/s)^{2} \\ & = 3500\; J \ldotp \end{split}$After the collision, $\begin{split} K_{f} & = \frac{1}{2} (M_{H} + M_{I}) v^{2} \\ & = \frac{1}{2} (70\; kg + 200\; kg)(2.67\; m/s)^{2} \\ & = 960\; J \ldotp \end{split}$Thus, there was a loss of 3500 J − 960 J = 2540 J.

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