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    • https://phys.libretexts.org/Bookshelves/Quantum_Mechanics/Quantum_Mechanics_III_(Chong)/06%3A_Appendices/6.02%3A_B-_The_Transfer_Matrix_Method
      Hence, ik[ψ+(xa)ψ(xa)]=ik+[ψ+(xb)ψ(xb)]. These two equations can be combined into a single matrix equation: \[\begin{bmatrix}1 & 1 \\ k...Hence, ik[ψ+(xa)ψ(xa)]=ik+[ψ+(xb)ψ(xb)]. These two equations can be combined into a single matrix equation: [11kk][ψ+(xa)ψ(xa)]=[11k+k+][ψ+(xb)ψ(xb)]. After doing a matrix inversion, this becomes \[\Psi_b = \mathbf{M}_s(k_+,k_-) \, \Psi_a, \;\;\;\mathrm{where}\…

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