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- https://phys.libretexts.org/Courses/Joliet_Junior_College/Physics_201_-_Fall_2019v2/Book%3A_Custom_Physics_textbook_for_JJC/03%3A_Vectors/3.09%3A_Products_of_Vectors_(Part_2)Another kind of vector multiplication is the vector product, also known as the cross product, which results in a vector perpendicular to both of the factors. The vector product has the distributive pr...Another kind of vector multiplication is the vector product, also known as the cross product, which results in a vector perpendicular to both of the factors. The vector product has the distributive property and the anticommutative property, and is obtained by multiplying the magnitudes of the two vectors by the sine of the angle between them. The direction of the vector product can be determined by the corkscrew right-hand rule.
- https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Physics_II_(2212)/06%3A_Sources_of_Magnetism_Magnetic_Forces_and_Fields/6.03%3A_Magnetic_Fields_and_LinesTo calculate the force, we use the given charge, velocity, and magnetic field and the definition of the magnetic force in cross-product form to calculate: \[\vec{F} = q\vec{v} \times \vec{B} = (3.2 \t...To calculate the force, we use the given charge, velocity, and magnetic field and the definition of the magnetic force in cross-product form to calculate: \[\vec{F} = q\vec{v} \times \vec{B} = (3.2 \times 10^{-19} C)((2.0 \hat{i} - 3.0 \hat{j} + 1.0 \hat{k}) \times 10^4 m/s) \times (1.5 \, T \hat{k})\] \[(-14.4 \hat{i} - 9.6 \hat{j}) \times 10^{-15}N.\] This solution can be rewritten in terms of a magnitude and angle in the xy-plane: \[|\vec{F}| = \sqrt{F_x^2 + F_y^2} = \sqrt{(-14.4)^2 + (-9.6)…
- https://phys.libretexts.org/Courses/Merrimack_College/Conservation_Laws_Newton's_Laws_and_Kinematics_version_2.0/07%3A_C7)_Conservation_of_Angular_Momentum_II/7.01%3A_The_Angular_Momentum_of_a_Point_and_The_Cross_ProductTo conclude this section, let me return to the angular momentum vector, and ask the question of whether, in general, the angular momentum of a rotating system, defined as the sum of the angular moment...To conclude this section, let me return to the angular momentum vector, and ask the question of whether, in general, the angular momentum of a rotating system, defined as the sum of the angular momentum over all the particles that make up the system, will or not satisfy the vector equation \(\vec L = I\vec{\omega}\).
- https://phys.libretexts.org/Bookshelves/Electricity_and_Magnetism/Electricity_and_Magnetism_(Tatum)/06%3A_The_Magnetic_Effect_of_an_Electric_Current/6.03%3A_Definition_of_the_Magnetic_FieldAs we move our wire around in the magnetic field, from one orientation to another, we notice that, while the direction of the force on it is always at right angles to the wire, the magnitude of the fo...As we move our wire around in the magnetic field, from one orientation to another, we notice that, while the direction of the force on it is always at right angles to the wire, the magnitude of the force depends on the orientation of the wire, being zero (by definition) when it is parallel to the field and greatest when it is perpendicular to it.
- https://phys.libretexts.org/Bookshelves/College_Physics/College_Physics_1e_(OpenStax)/10%3A_Rotational_Motion_and_Angular_Momentum/10.07%3A_Gyroscopic_Effects-_Vector_Aspects_of_Angular_MomentumThe direction of angular velocity \(\omega\) size and angular momentum \(L\) are defined to be the direction in which the thumb of your right hand points when you curl your fingers in the direction of...The direction of angular velocity \(\omega\) size and angular momentum \(L\) are defined to be the direction in which the thumb of your right hand points when you curl your fingers in the direction of the disk’s rotation as shown. This torque creates a change in angular momentum \(L\) in the same direction, perpendicular to the original angular momentum \(L\), thus changing the direction of \(L\) but not the magnitude of \(L\).
- https://phys.libretexts.org/Courses/Georgia_State_University/GSU-TM-Physics_I_(2211)/04%3A_Forces/4.09%3A_Common_Forces_-_Magnetic_ForceTo calculate the force, we use the given charge, velocity, and magnetic field and the definition of the magnetic force in cross-product form to calculate: \[\vec{F} = q\vec{v} \times \vec{B} = (3.2 \t...To calculate the force, we use the given charge, velocity, and magnetic field and the definition of the magnetic force in cross-product form to calculate: \[\vec{F} = q\vec{v} \times \vec{B} = (3.2 \times 10^{-19} C)((2.0 \hat{i} - 3.0 \hat{j} + 1.0 \hat{k}) \times 10^4 m/s) \times (1.5 \, T \hat{k})\] \[(-14.4 \hat{i} - 9.6 \hat{j}) \times 10^{-15}N.\] This solution can be rewritten in terms of a magnitude and angle in the xy-plane: \[|\vec{F}| = \sqrt{F_x^2 + F_y^2} = \sqrt{(-14.4)^2 + (-9.6)…
- https://phys.libretexts.org/Courses/Joliet_Junior_College/Physics_201_-_Fall_2019/Book%3A_Physics_(Boundless)/03%3A_Vectors/3.09%3A_Products_of_Vectors_(Part_2)Another kind of vector multiplication is the vector product, also known as the cross product, which results in a vector perpendicular to both of the factors. The vector product has the distributive pr...Another kind of vector multiplication is the vector product, also known as the cross product, which results in a vector perpendicular to both of the factors. The vector product has the distributive property and the anticommutative property, and is obtained by multiplying the magnitudes of the two vectors by the sine of the angle between them. The direction of the vector product can be determined by the corkscrew right-hand rule.
- https://phys.libretexts.org/Courses/Muhlenberg_College/MC%3A_Physics_121_-_General_Physics_I/03%3A_Vectors/3.09%3A_Products_of_Vectors_(Part_2)Another kind of vector multiplication is the vector product, also known as the cross product, which results in a vector perpendicular to both of the factors. The vector product has the distributive pr...Another kind of vector multiplication is the vector product, also known as the cross product, which results in a vector perpendicular to both of the factors. The vector product has the distributive property and the anticommutative property, and is obtained by multiplying the magnitudes of the two vectors by the sine of the angle between them. The direction of the vector product can be determined by the corkscrew right-hand rule.
- https://phys.libretexts.org/Courses/Gettysburg_College/Gettysburg_College_Physics_for_Physics_Majors/07%3A_C7)_Conservation_of_Angular_Momentum_II/7.01%3A_The_Angular_Momentum_of_a_Point_and_The_Cross_ProductTo conclude this section, let me return to the angular momentum vector, and ask the question of whether, in general, the angular momentum of a rotating system, defined as the sum of Equation 6.1.4 ove...To conclude this section, let me return to the angular momentum vector, and ask the question of whether, in general, the angular momentum of a rotating system, defined as the sum of Equation 6.1.4 over all the particles that make up the system, will or not satisfy the vector equation \(\vec L = I\omega\).
- https://phys.libretexts.org/Bookshelves/University_Physics/University_Physics_(OpenStax)/Book%3A_University_Physics_I_-_Mechanics_Sound_Oscillations_and_Waves_(OpenStax)/02%3A_Vectors/2.09%3A_Products_of_Vectors_(Part_2)Another kind of vector multiplication is the vector product, also known as the cross product, which results in a vector perpendicular to both of the factors. The vector product has the distributive pr...Another kind of vector multiplication is the vector product, also known as the cross product, which results in a vector perpendicular to both of the factors. The vector product has the distributive property and the anticommutative property, and is obtained by multiplying the magnitudes of the two vectors by the sine of the angle between them. The direction of the vector product can be determined by the corkscrew right-hand rule.
- https://phys.libretexts.org/Bookshelves/Classical_Mechanics/Classical_Mechanics_(Dourmashkin)/19%3A_Angular_Momentum/19.02%3A_Angular_Momentum_about_a_Point_for_a_ParticleDefine the angular momentum \(\overrightarrow{\mathbf{L}}_{s}\) about the point \(S\) of a point-like particle as the vector product of the vector from the point \(S\) to the location of the object wi...Define the angular momentum \(\overrightarrow{\mathbf{L}}_{s}\) about the point \(S\) of a point-like particle as the vector product of the vector from the point \(S\) to the location of the object with the momentum of the particle,
