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19.10: Alternating-Current Circuits (Answers)
https://phys.libretexts.org/Courses/Kettering_University/Electricity_and_Magnetism_with_Applications_to_Amateur_Radio_and_Wireless_Technology/19%3A_Alternating-Current_(AC)_Circuits/19.10%3A_Alternating-Current_Circuits_(Answers)
d. $\displaystyle 1100Ω$ , 0.092 A, $\displaystyle I=(0.092A)sin(1000πt+1.09)$ The reactance of the capacitor is larger than the reactance of the inductor because the current leads the voltage. a. ...d. $\displaystyle 1100Ω$ , 0.092 A, $\displaystyle I=(0.092A)sin(1000πt+1.09)$ The reactance of the capacitor is larger than the reactance of the inductor because the current leads the voltage. a. $\displaystyle \frac{v_{out}}{v_{in}}=\frac{1}{\sqrt{1+1/ω^2R^2C^2}}$ and $\displaystyle \frac{v_{out}}{v_{in}}=\frac{ωL}{\sqrt{R^2+ω^2L^2}}; b. \(\displaystyle v_{out}≈v_{in}$ and $\displaystyle v_{out}≈0$

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