If the skater has a length L and the center of mass is in the middle of the skater, the sum of the torques about the center of mass is given by the torques from the normal forces and the force of ...If the skater has a length L and the center of mass is in the middle of the skater, the sum of the torques about the center of mass is given by the torques from the normal forces and the force of friction: ∑τ=τNz+τfsz=L2cosθN−L2sinθfs About the center of mass, the torques must be zero for the skater not to rotate, and this would give a relation between the force of static friction and the normal fo…
