Inside the volume of the sphere, we still use a gaussian spherical surface of radius, r, so that the flux is given by: ∮→E⋅d→A=4πr2E However...Inside the volume of the sphere, we still use a gaussian spherical surface of radius, r, so that the flux is given by: ∮→E⋅d→A=4πr2E However, inside the sphere, the gaussian surface only encloses the charge up to a radius of r, which we find by integration, similar to part a): Qenc=∫dQ=∫r04aπr4dr=45aπr5 Applying Gauss’ Law: \[\begin{aligned} \oint \vec E\cdot d\vec A&…
