The potential difference is however dependent on the (constant) capacitance of the capacitor, and the amount of charge, q, already stored on the plates: \[\begin{aligned} q &= C\Delta V\\ \therefo...The potential difference is however dependent on the (constant) capacitance of the capacitor, and the amount of charge, q, already stored on the plates: q=CΔV∴ In order to determine the work required to transfer a total amount of charge, Q, we sum the work in transferring each infinitesimal charge, dq: \[\begin{aligned} W=\int dW=\int_0^Q \Delta Vdq=\int_0^Q \frac{q}{C}dq=\frac{1}{2}\frac{Q^2}{C}\end{aligned…
