To find the charge stored in the capacitor at \(t = 2\text{s}\), we can use the function \(Q(t)\) that we determined before: \[\begin{aligned} Q(t=2\text{s})=Q_0 e^{-\frac{t}{RC}}\end{aligned}\] where...To find the charge stored in the capacitor at \(t = 2\text{s}\), we can use the function \(Q(t)\) that we determined before: \[\begin{aligned} Q(t=2\text{s})=Q_0 e^{-\frac{t}{RC}}\end{aligned}\] where we can determine, \(Q_0\), now that we know the capacitance. \(Q_0\) is the charge on the capacitor at time \(t=0\), when the voltage across the capacitor is \(9\text{V}\): \[\begin{aligned} Q_0=C\Delta V = (0.56\text{F})(9\text{V})=5.0\text{C}\end{aligned}\] At \(t = 2\text{s}\), the charge on th…
