The voltage in the primary coil is given by Faraday’s Law: \[\begin{aligned} \Delta V_p = N_p \frac{d\Phi_B}{dt}\end{aligned}\] as is the voltage in the secondary coil: \[\begin{aligned} \Delta V_s = ...The voltage in the primary coil is given by Faraday’s Law: \[\begin{aligned} \Delta V_p = N_p \frac{d\Phi_B}{dt}\end{aligned}\] as is the voltage in the secondary coil: \[\begin{aligned} \Delta V_s = N_s \frac{d\Phi_B}{dt}\end{aligned}\] Since the flux (and thus its time-derivative) are the same in both coils, we can isolate the time-derivative in each equation to obtain the relationship between the voltages in the two coils: \[\begin{aligned} \frac{\Delta V_p}{N_p}&=\frac{\Delta V_s}{N_s}\\ \t…
